Aptitude - Simple Interest - Discussion

IN SI, the principal is always same, but in CI principal get vary ie, (p+ci) this is the concept.

You can take an example for it and find CI and SI for single case. you will see SI is always found in original principal, whether it is for 1st, 2nd yr and so on.

But for CI, interest always find on (p+interest), every year principal gets changed which will be( p+interest).

So the ans is correct ie 115.

It is S.I.

For 1st yr he has to pay (200 x 1 x 5/100) = 10 (interest only),
Now he cleared Rs. 100. So remaining principle is (200-100) = rs. 100.
Hence, he has to pay (100 x 1 x 5/100) = 5 (interest only).
So, In total he has to pay [10(prv int.) + 5 (nxt int) + 100 (remaining principle)] = rs. 115.

Is it clear?

115 is the clear answer.

Because I have 200 /- for 3 years with 5% simple interest. So its interest will be 30/- and totally become 230/-. If you solve this problem year by year its interest will be 231.525/- as for one year si is 10/- and sum is 210/- for second year si is 10. 5/- and sum is 220.5/- for 3rd year SI is 11.025 so the total sum is 231.525 so you can easily understand.

The Basic Rule: Any sum that is paid back to the bank before the last installment is deducted from the principal and not from the interest.

So, the answer is 115 calculated using SI.

->(200*5*1)/100=10.
200+10=210(principal + SI)
He returns 100 at the end of the year,
210-100=110.

->(110*5*1)/100=5.5.
110+5.5=115.50.
He has to pay 115.50 at the end of the second year.

Answer is correct as;

--> 1. firstly calculate the SI for the first year that comes to be 10rs.

2.Then he returned 100rs at the end of the first year so remaining amount to be paid is 100 + 10.

3.Now for the second yr the SI will be calculated on 100rs which comes to be 5rs. So total amount to be paid at the end of second yr is 100 + 10 + 5 =115.

The Answer is correct.

First, he takes 200$ loan from the bank.

So, for first 1 year duration the interest value is = (200*1*5/100) = 10$.
Then, he gives back $100 so net amount he has on which simple interest will apply is 100 because of simple interest take account only initially invested money.

So, for 2nd-year interest =(100*1*5/100)=5$.
So the total amount he gives back after the end of 2nd year = 100+10+5=115 (Principal amount remaining after 1st year + 1st-year interest+2nd-year interest).

(200*5v1)/100 = 10.
(110*5*1)/100 = 5.5.
110+5.5 = 115.5.

115 is the right answer because simple interest calculates on 100 not on 110. It is not C I.

115 is the right answer. The first thing this question is based on simple interest, so for the second year, interest money will not be added with the rest of the principal money. after one-year total interest will be:

(200 x 5 x 1)/100 = 10 -> first-year interest = 10 Rs -- this money will not add up with principal for next year.

And he paid 100 Rs in the last one year so the rest of the money is 200-100 = 100.
Now we will calculate interest for 100 Rs for 2nd year -- ( 100 x 5 x 1 )/100 = 5 Rs.

So total money after 2nd year he has to pay = ( 100 + 10 + 5 ) = 115.