Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 14)
14.
A person takes a loan of Rs. 200 at 5% simple interest. He returns Rs. 100 at the end of 1 year. In order to clear his dues at the end of 2 years, he would pay:
Answer: Option
Explanation:
| Amount to be paid |
|
|||||||||
| = Rs. 115. |
Discussion:
83 comments Page 6 of 9.
ER. MAYANK JAIN said:
1 decade ago
The answer is correct as it is based on simple interest, according to SI interest must be calculated only to initial sum borrowed.
Ritesh said:
1 decade ago
For first year S.I = 200*5*1/100 = 10 so total amount he needs to pay at the end of 1 year = 10+200 = 210.
He paid 100 so rest amount = 210-100 = 110(100+10)(10 is the interest).
Now instead of 110 the principal will be 100 for the next year.(interest is calculated on principal value in case of S.I).
So S.I = 100*5*1/100 = 5(interest).
So he will pay 100+10+5 = 115.
He paid 100 so rest amount = 210-100 = 110(100+10)(10 is the interest).
Now instead of 110 the principal will be 100 for the next year.(interest is calculated on principal value in case of S.I).
So S.I = 100*5*1/100 = 5(interest).
So he will pay 100+10+5 = 115.
Suman saurav said:
1 decade ago
According to question solution is wrong. In the question it should be mention that the 100 rupees returned after 1 yr. is from the principal. Otherwise there should not be option of 115.50.
Sreehari said:
1 decade ago
Hello all.
115 is the correct answer.
200*0.05 = 210. But he paid 100. So, though the remaining amount is 110, interest is only for 100 as the case is simple interest. So 5 Rs on 100 plus 210-100. If this is the case of compound interest then, answer is 115.5, for now its 115.
115 is the correct answer.
200*0.05 = 210. But he paid 100. So, though the remaining amount is 110, interest is only for 100 as the case is simple interest. So 5 Rs on 100 plus 210-100. If this is the case of compound interest then, answer is 115.5, for now its 115.
Gayathridevi said:
1 decade ago
Answer is correct.
Consider for 200, totally he has to pay = 200+(200*2*5)/100 = 220.
= P+(PTR)/100 = 220.
Remove that returned 100/-and that interest from 220.
= 220-(100+(100*1*5)/100) = 220-105 = 105. Which is answer?
Consider for 200, totally he has to pay = 200+(200*2*5)/100 = 220.
= P+(PTR)/100 = 220.
Remove that returned 100/-and that interest from 220.
= 220-(100+(100*1*5)/100) = 220-105 = 105. Which is answer?
Prasanthi said:
1 decade ago
Hey the answer should b 115.5.
Because for the last 1 year, the SI is calculated as (210-100)*1*5/100 which is 5.5/-.
So the total amount to be re payed now is 110+5.5 rupees.
Because for the last 1 year, the SI is calculated as (210-100)*1*5/100 which is 5.5/-.
So the total amount to be re payed now is 110+5.5 rupees.
Trishul said:
1 decade ago
The question is not clear here. There are two cases:.
1) If Rs. 100 he paid at the end of 1st year is used to first clear the interest of Rs. 10 generated, then answer will come Rs. 115.50/-.
2) If Rs. 100 he paid at the end of 1st year is only used to reduce the principle amount, then answer comes as Rs. 115/-.
Because it is simple interest and only the principle amount, not interest amount, is used to calculate interest.
1) If Rs. 100 he paid at the end of 1st year is used to first clear the interest of Rs. 10 generated, then answer will come Rs. 115.50/-.
2) If Rs. 100 he paid at the end of 1st year is only used to reduce the principle amount, then answer comes as Rs. 115/-.
Because it is simple interest and only the principle amount, not interest amount, is used to calculate interest.
Sarath said:
1 decade ago
Friends question is clear he taken loan Rs. 200 for two years so,
1st calculate simple interest for 2 years.
i.e S.I = 200*5*2/100 = 20.
So total amount = 200+20 = 220.
So he returns 100 rupees in 1st year = 220-100 = 120.
Rs. 120 is a right answer.
And 1st year he didn't give he give only Rs. 100.
1st calculate simple interest for 2 years.
i.e S.I = 200*5*2/100 = 20.
So total amount = 200+20 = 220.
So he returns 100 rupees in 1st year = 220-100 = 120.
Rs. 120 is a right answer.
And 1st year he didn't give he give only Rs. 100.
Ram Kr Prajapati said:
1 decade ago
Its answer is wrong.
Right answer is = 115.5.
Solution:
If he wants to clear his loan in 1 year then he has to pay:
200+[(200*5*1)/100] = 210.
But he only pay 100 rupees at the end of 1 year, so he is in debt of rupees = (210-100) = 110;
Now if he wants to remove all his debt in end of 2nd year.
Then he has to pay : 110+{(110*5*1)/100)}.
= 115.5.
Right answer is = 115.5.
Solution:
If he wants to clear his loan in 1 year then he has to pay:
200+[(200*5*1)/100] = 210.
But he only pay 100 rupees at the end of 1 year, so he is in debt of rupees = (210-100) = 110;
Now if he wants to remove all his debt in end of 2nd year.
Then he has to pay : 110+{(110*5*1)/100)}.
= 115.5.
Abhishek PPLO said:
10 years ago
After 1st year, SI was 10, amount at the end of 1st year to paid is 210 and he paid 100, so remaining amount is 110.
Next year, SI will be on 110, so SI is coming out to be 5.5, and amount to be paid is 115.5.
Next year, SI will be on 110, so SI is coming out to be 5.5, and amount to be paid is 115.5.
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