Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 12)
12.
What will be the ratio of simple interest earned by certain amount at the same rate of interest for 6 years and that for 9 years?
Answer: Option
Explanation:
Let the principal be P and rate of interest be R%.
 Required ratio = |
|
= | 6PR | = | 6 | = 2 : 3. | ||||
|
9PR | 9 |
Video Explanation: https://youtu.be/GaaEDwTWc6w
Discussion:
16 comments Page 2 of 2.
Karthik said:
4 years ago
Easy way;
Just assume 100 as principle 10 %percetage interest.
So 6years it becomes 160 interest is 60,
9 years it becomes 190 interest 90.
60:90 = 2:3.
Just assume 100 as principle 10 %percetage interest.
So 6years it becomes 160 interest is 60,
9 years it becomes 190 interest 90.
60:90 = 2:3.
(1)
Anomy said:
4 years ago
@Amrik Singh,
The Rate of interest and principal are constant. As time lies, in the numerator of the formula. The interests will be directly proportional to time.
The Rate of interest and principal are constant. As time lies, in the numerator of the formula. The interests will be directly proportional to time.
(1)
Sulthan shareef said:
3 years ago
PTR/PTR.
PR6/PR9,
PR = 6/9,
PR = 2/3.
P:R = 2:3.
PR6/PR9,
PR = 6/9,
PR = 2/3.
P:R = 2:3.
Aruna said:
2 years ago
@All.
I think there is No change in the rate of interest.
So, 6:9=2:3.
I think there is No change in the rate of interest.
So, 6:9=2:3.
Kyomuhendo Marvin said:
2 years ago
We Know,
SI = [(P*R*T)/100].
Lets Assume P = 100, R = 3%.
Therefore,
SI = [(100*3*6)/100) : [(100*3*9)/100].
= 18 : 27.
= 18/27.
= 2:3.
SI = [(P*R*T)/100].
Lets Assume P = 100, R = 3%.
Therefore,
SI = [(100*3*6)/100) : [(100*3*9)/100].
= 18 : 27.
= 18/27.
= 2:3.
(1)
Riya said:
3 months ago
When the principal and rate of interest are constant, then Simple interest is directly proportional to time.
So, here the answer is 2:3.
So, here the answer is 2:3.
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