Aptitude - Simple Interest - Discussion

We have 1750 as interest.
Let say this is our 100% interest so, we have to find 102% interest .
That's it just cross multiply .
100=1750.
102=?
(1750 * 102)/100 = 35 rs.

Question is "how much more interest would it have earned?". So we already have simple interest of Rs. 1750.

So, 2% of 1750 will be 35.

Please correct if I'm wrong.

s.i = p * 7 * r/100 = 1750.
If rate of interest increses by 2% then p * 7 * 1.02r/100 = 1750 * 1.02 = 1785.

The extra interest he will get = 1785 - 1750 = 35.

pr = 1750/7 = 250
r = 250/p.

2% more => 250/p + [250/p]*2%=255/p is the new r.
SI = p * 255/p * 7 = 1785.

1785 - 1750 = 35 rupees more.

ANS : 245.

Interest is increased by 2% more,so (7 years) x 2% = 14%.
Interest is 1750, so now 1750 + 14% = 1995.
The difference between 1995-1750 = 245.

"Had the interest been 2% more, " - S.I is increased by 2% right? not the Rate of Interest (R).

All the solution are based on the percentage of a ate of interest. But if you don't know the actual amount how could you say that the 2% of this amount will be this?

@All.

Hi, Let me explain.

The answer the author comes up is actually correct.

While we think we can solve this problem by applying 'let x' solution, we are not, however.

This is because we are playing with the rate here and rate(%) is very tricky. Try to solve using 10% rate, you get 350. However, try to use another rate, say, 5%, you get 700 as the difference between the old rate and the plus 2 rate.

I believe in them by saying this question's answer is indeterminable due to lack of data reason.

The Answer is 35.

Since the rate is increased by 2% so the S.I gets increased by 2%.
2% of 1750 = 35.

Consider the initial rate of interest be 10%, then the principle is calculated to be 2000. Using 12% rate of interest the new SI is 2100. So the answer is Rs. 350.