Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 13)
13.
A certain amount earns simple interest of Rs. 1750 after 7 years. Had the interest been 2% more, how much more interest would it have earned?
Answer: Option
Explanation:
We need to know the S.I., principal and time to find the rate.
Since the principal is not given, so data is inadequate.
Discussion:
98 comments Page 4 of 10.
Megha said:
8 years ago
Why don't we assume 100 as a principal?
Can anyone answer this?
Can anyone answer this?
Saumya said:
8 years ago
35 is the correct answer.
Swati said:
8 years ago
Correct answer is 35.
Sanju manna said:
6 years ago
Here the answer is 35.
Because 2% is not the increasing percentage of rate of interest it is only the increase in the total interest which is given below.
So, the 2% of 1750 is 35.
Because 2% is not the increasing percentage of rate of interest it is only the increase in the total interest which is given below.
So, the 2% of 1750 is 35.
D Misra said:
3 weeks ago
1750 = prt/100
1750 x 100 = pr x 7
175000/7r = p ---> (1)
100 x SI = p x 1.02r x 7.
(100 x SI)/7.14r = p ---> (2)
(1) = (2).
175000/7r = (100 x SI)/7.14r,
1750 = SI/1.02,
SI = 1785.
Difference 1785 - 1750 = 35.
1750 x 100 = pr x 7
175000/7r = p ---> (1)
100 x SI = p x 1.02r x 7.
(100 x SI)/7.14r = p ---> (2)
(1) = (2).
175000/7r = (100 x SI)/7.14r,
1750 = SI/1.02,
SI = 1785.
Difference 1785 - 1750 = 35.
Nagurvargani said:
7 months ago
No, @Jaimunis.
1750/7=250 is the correct answer.
1750/7=250 is the correct answer.
Pema said:
4 years ago
We can find the principle by using this formula but we need to assume the interest rate.
P = si/(r*t).
P = si/(r*t).
Dilip said:
5 years ago
r is rate of interest.
Increased rate of interest is 1.02r because increased rate is 2%= (2÷100).
p*7*r=1750*100 ==> eq 1.
p*7*1.02*r=(1750+x)100==> eq 2 (x is incresed rs).
eq1& 2 is written as below.
7pr=175000 ==>eq 3.
7.14pr=175000+100x==> eq 4.
Upon solving both eqn 3*4.
0.14pr=100x==>eq 5.
by solving eqn 1 we get pr=25000.
By substituting that in eq 5.
0.14*250 = x.
so, x = 35.
Increased rate of interest is 1.02r because increased rate is 2%= (2÷100).
p*7*r=1750*100 ==> eq 1.
p*7*1.02*r=(1750+x)100==> eq 2 (x is incresed rs).
eq1& 2 is written as below.
7pr=175000 ==>eq 3.
7.14pr=175000+100x==> eq 4.
Upon solving both eqn 3*4.
0.14pr=100x==>eq 5.
by solving eqn 1 we get pr=25000.
By substituting that in eq 5.
0.14*250 = x.
so, x = 35.
SUSMITHA said:
5 years ago
As per my knowledge answer is 245.
SI for 7 years =1750.
RoI increases 2% means 7years *2% =14% increased so;
100% ------ 1750 means,
114% ------ =( 1750*114) /100 = 1995,
Interest increased = 1995-1750 = 245.
SI for 7 years =1750.
RoI increases 2% means 7years *2% =14% increased so;
100% ------ 1750 means,
114% ------ =( 1750*114) /100 = 1995,
Interest increased = 1995-1750 = 245.
Abhinav said:
5 years ago
According to me, the correct answer is 35.
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