Aptitude - Simple Interest - Discussion

1750 = prt/100
1750 x 100 = pr x 7
175000/7r = p ---> (1)

100 x SI = p x 1.02r x 7.
(100 x SI)/7.14r = p ---> (2)

(1) = (2).
175000/7r = (100 x SI)/7.14r,
1750 = SI/1.02,
SI = 1785.

Difference 1785 - 1750 = 35.

As per data specified p and yr are constant only rates changes.
Moreover, SI is directly proportional.
So, I think the answer would be 35.

The Answer is 35.

Equation One = 7*P*R/100=1750
to be found (7*P*R+2)/100 = ?
we can rewrite as (7*P*R)100 + 2/100 = ?
and then 1750 + 2/100 = 35.

I think the answer should be 35. I am not getting why they are saying data inadequate.

Old interest=(P*R*7)/100= 1750.

New interest= [P*R*7*(102/100)]/100.
=[(P*R*7)/100]*[102*100].
=1750*(102/100),
=1785.

So, the answer is = New Interest- Old interest = 1785 - 1750 = 35.

1750 divided by 7 give Interest for one year ie, Rs 250.

Here, 2% of 250 is 5.
So if the interest is increased by 2% then the Interest for one year will 255.
So for 7 years 1785.
Thus the difference will be Rs 35.

1750 = PR7/100.

=>PR = 25000-----(1).

Again,
SI = (P*102/100*R*7) / 100.

=>PR = (100*100*SI) / 7*102------(2).

By equating (1) and (2).

SI = 1785.

So ans is 1785-1750 = 35.

The answer is Rs. 35.

Because the 2% more is on Simple Interest and not on the interest rate. Therefore we can directly find 2% of given simple interest in one year and multiply by 7.

Here in the first case;

P * 7 * R/100 = 1750 -----> (1)
And in the second case interest is increased by 2%( Rate of interest).

P*7*(R+2)/100=? -------> (2)

HERE THE Rate of Interest is R+2 because the 100 in the demo is for the Rate of Interest Calculation i.e., R/100 is R%.

So, by the two equations, we get 3 unknown values. But to solve 3 unknown values we need 3 equations. hence there is no solution for this question unless one of the 3 unknown values is given.

I agree with you @Sooraj.

35 is the correct answer according to me.