Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 13)
13.
A certain amount earns simple interest of Rs. 1750 after 7 years. Had the interest been 2% more, how much more interest would it have earned?
Answer: Option
Explanation:
We need to know the S.I., principal and time to find the rate.
Since the principal is not given, so data is inadequate.
Discussion:
97 comments Page 2 of 10.
Vasanth said:
1 decade ago
If are increased by 2% interest becomes 1.02r.
Vijay said:
1 decade ago
Here the ans is sp=3500
prinicipal amount is same so p1=p2=x,time is same,the rate is different r,2r
p1=p2
sp1*100/t1r2=sp2*100/t2r2
1750/(7*r)=sp/(7*2r)
sp=3500
so sp2-sp1=1750
prinicipal amount is same so p1=p2=x,time is same,the rate is different r,2r
p1=p2
sp1*100/t1r2=sp2*100/t2r2
1750/(7*r)=sp/(7*2r)
sp=3500
so sp2-sp1=1750
Satyajit Das said:
1 decade ago
1750 = PR7/100.
=>PR = 25000-----(1).
Again,
SI = (P*102/100*R*7) / 100.
=>PR = (100*100*SI) / 7*102------(2).
By equating (1) and (2).
SI = 1785.
So ans is 1785-1750 = 35.
=>PR = 25000-----(1).
Again,
SI = (P*102/100*R*7) / 100.
=>PR = (100*100*SI) / 7*102------(2).
By equating (1) and (2).
SI = 1785.
So ans is 1785-1750 = 35.
(1)
Anusha said:
1 decade ago
@Satyajit das.
You said that si= (p*102/100*R*7)/100.
How it will come?
Mainly I want the number 102 from where it has come?
That equation 2 is also same doubt.
Can you explain me briefly?
You said that si= (p*102/100*R*7)/100.
How it will come?
Mainly I want the number 102 from where it has come?
That equation 2 is also same doubt.
Can you explain me briefly?
Satyajit dash said:
1 decade ago
Hi @Anusha,
As in question given, 2% more interest than the first case,
So, rate of interest = r+(2r/100) = 102r/100.
Hope understood.
As in question given, 2% more interest than the first case,
So, rate of interest = r+(2r/100) = 102r/100.
Hope understood.
Waseem Khan said:
1 decade ago
I think 245 is correct as they asked for Increase in interest. So 2% of total interest earned for 7 year is 245. Please clarify me if it is wrong one.
Vikramjeet said:
1 decade ago
Hey friends it was said that when no principal amount given then take 100 =p so why we can't write this value.
Promish said:
1 decade ago
Hey friends I think the answer will be option A i.e. 35,
Explanation:
let r be 100,and it is increased by 2% for second case, so for the second case r will be 102.
I = Rs. 1750, t=7 yrs, r=100(let).
So P = (I*100)/r*t=(1750*100)/(100*7) = 250.
So use this P for the second case,and S.I will be,
I = (P*t*r)/100=(250*7*102)/100 = 1785.
So the increase will be = Rs.(1785-1750) = Rs.35.
Explanation:
let r be 100,and it is increased by 2% for second case, so for the second case r will be 102.
I = Rs. 1750, t=7 yrs, r=100(let).
So P = (I*100)/r*t=(1750*100)/(100*7) = 250.
So use this P for the second case,and S.I will be,
I = (P*t*r)/100=(250*7*102)/100 = 1785.
So the increase will be = Rs.(1785-1750) = Rs.35.
Arjun said:
1 decade ago
Ans: B.
In the 1st case: S.I = 245R/2 (Let, R =Rate of Interest).
In the 2nd case: S.I = (245R/2+490/2).
So, in the 2nd case we have Rs.245 extra.
In the 1st case: S.I = 245R/2 (Let, R =Rate of Interest).
In the 2nd case: S.I = (245R/2+490/2).
So, in the 2nd case we have Rs.245 extra.
Rahul said:
1 decade ago
Let the rate of S.I is 100 (initially).
In the first case:
Sum = (S.I x 100)/(Rate of interest x time).
So sum = (1750 x 100)/(100 x 7) = 250.
In the 2nd case:
The interest rate is 2% more, so the interest rate is 102%.
S.I = (sum x time x Rate of interest)/100.
= (250 x 7 x 102)/100 = 1785.
So the gain in S.I is (1785-1750) = 35.
Thank You.
In the first case:
Sum = (S.I x 100)/(Rate of interest x time).
So sum = (1750 x 100)/(100 x 7) = 250.
In the 2nd case:
The interest rate is 2% more, so the interest rate is 102%.
S.I = (sum x time x Rate of interest)/100.
= (250 x 7 x 102)/100 = 1785.
So the gain in S.I is (1785-1750) = 35.
Thank You.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers