Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 12)
12.
A runs 1
times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time?
times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time?
Answer: Option
Explanation:
| Ratio of the speeds of A and B = | 5 | : 1 = 5 : 3. |
| 3 |
Thus, in race of 5 m, A gains 2 m over B.
2 m are gained by A in a race of 5 m.
| 80 m will be gained by A in race of |  |
5 | x 80 |  m |
= 200 m. |
| 2 |
Winning post is 200 m away from the starting point.
Discussion:
15 comments Page 2 of 2.
Anu said:
8 years ago
A runs 1 2/3 times faster than B so it can be written as (1*3+2)/3 : 1 => 5/3 :1.On taking LCM we have 5 : 3
Salman said:
8 years ago
If A runs 1 times as fast as B then how can be the ratio is 5:3?
It should be 2:1.
It should be 2:1.
Kani said:
1 decade ago
I can't understand please explain by shortcuts.
Md. Iqbal Hasan said:
4 years ago
Awesome explanation. Thanks @Shivakrishna.
(1)
Gowthami said:
1 decade ago
Can you explain briefly any one?
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