Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 31)
31.
Two, trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is:
Answer: Option
Explanation:
Let us name the trains as A and B. Then,
(A's speed) : (B's speed) = b : a = 16 : 9 = 4 : 3.
Discussion:
108 comments Page 3 of 11.
Santosh parmar said:
7 years ago
Thanks all for explaining this.
(1)
Anil said:
6 years ago
Why are getting the square root. Can anyone explain to me?
(1)
Ishu shrivastava said:
6 years ago
Solving the eqns..
D=(v1+v2)t ---------> 1
D=(t+9)v1---------> 2
D=(t+16)v2---------> 3.
Putting the value of t from eq 1 in eq 2 & 3 then taking all the term having D on one side and then taking ratio of eq.2 & 3.
And we will get v1/v2=√16/√9= 4/3.
D=(v1+v2)t ---------> 1
D=(t+9)v1---------> 2
D=(t+16)v2---------> 3.
Putting the value of t from eq 1 in eq 2 & 3 then taking all the term having D on one side and then taking ratio of eq.2 & 3.
And we will get v1/v2=√16/√9= 4/3.
(1)
Ahaji Victor said:
6 years ago
The correct answer is 4/3 because in the question both trains meets with each other before the now covered their remaining distance in 9hr and 16hrs respectively.
(1)
Gayathri said:
1 year ago
Thanks everyone for explaining the answer.
(1)
Bhargav said:
2 decades ago
Speed = Distance/Time; Then how will you write root of time?
Vinod said:
1 decade ago
How can you calculate speed as the square-root of time?
Kiran.p said:
1 decade ago
PARTH said:
1 decade ago
Can someone prove that?
Karunakaran said:
1 decade ago
Let distance = x, a as speed of train a & b as speed of train b
9 x a = x
16 x b= x
9a = 16b
a/b = 16/9, simplify this with square root both up & down we get 4/3 & ratio 4:3.
9 x a = x
16 x b= x
9a = 16b
a/b = 16/9, simplify this with square root both up & down we get 4/3 & ratio 4:3.
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