# Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 30)

30.

Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?

Answer: Option

Explanation:

Suppose they meet *x* hours after 7 a.m.

Distance covered by A in *x* hours = 20*x* km.

Distance covered by B in (*x* - 1) hours = 25(*x* - 1) km.

20*x* + 25(*x* - 1) = 110

45*x* = 135

*x* = 3.

So, they meet at 10 a.m.

Discussion:

90 comments Page 9 of 9.
Nayana said:
1 decade ago

@Randhir

In the problem what you have solved above,the distance between point A and B is 6Y. I am not getting how you got 6Y. Can you please explain me that?

In the problem what you have solved above,the distance between point A and B is 6Y. I am not getting how you got 6Y. Can you please explain me that?

Mahe said:
1 decade ago

@Faisel,

If they meet 8am then

Distance covered by b in xhrs is 25x

Distance covered by a in(X+1)HRS=20(X+1)

(x+1) coz v r considering 1 hr aft train A has started..

So,

25X+20(X+1)=110

45X=90

X=2

Hence 8am + 2 = 10am

If they meet 8am then

Distance covered by b in xhrs is 25x

Distance covered by a in(X+1)HRS=20(X+1)

(x+1) coz v r considering 1 hr aft train A has started..

So,

25X+20(X+1)=110

45X=90

X=2

Hence 8am + 2 = 10am

Faisal said:
1 decade ago

what if we say they meet after 8AM

Distance covered by B in x Hrs =25X

Distance covered by A in (x-1)Hrs = 20(x-1)

25x+20(x-1)=110

25x+20x-20=110

25x+20x=130

45x=130

x= 2.8 ( Which in incorrect how come )

Distance covered by B in x Hrs =25X

Distance covered by A in (x-1)Hrs = 20(x-1)

25x+20(x-1)=110

25x+20x-20=110

25x+20x=130

45x=130

x= 2.8 ( Which in incorrect how come )

Easwar said:
1 decade ago

Hi Erererer,

It was assumed that trains r meeting after x hours,

so 5 pm(starting time) + 3.20 = 8.20pm

Thanks Randhir.....

It was assumed that trains r meeting after x hours,

so 5 pm(starting time) + 3.20 = 8.20pm

Thanks Randhir.....

Erererer said:
1 decade ago

X=3 how it convet to 10 am

Randhir said:
1 decade ago

hi Easwar,

The speed of one train is twice the other so let

speed of 1st train is Y.

speed of 2nd train is 2Y.

then distance between point A and B is 6Y.

Suppose they meet x hours after 5 a.m.

Distance covered by 1st train in X hours = YX km.

Distance covered by B in (X - 2) hours = 2Y(X - 2) km.

Therefore YX + 2Y(X - 2) = 6Y

=> YX + 2YX - 4Y = 6Y

=> 3YX = 10Y

=> X =10 / 3 (in hours)

=> X =10/3*60 (because converting into minutes)

=> X =200 minutes

200 minutes means 3 hour 20 minutes

So, they meet at 8 : 20 p.m.

The speed of one train is twice the other so let

speed of 1st train is Y.

speed of 2nd train is 2Y.

then distance between point A and B is 6Y.

Suppose they meet x hours after 5 a.m.

Distance covered by 1st train in X hours = YX km.

Distance covered by B in (X - 2) hours = 2Y(X - 2) km.

Therefore YX + 2Y(X - 2) = 6Y

=> YX + 2YX - 4Y = 6Y

=> 3YX = 10Y

=> X =10 / 3 (in hours)

=> X =10/3*60 (because converting into minutes)

=> X =200 minutes

200 minutes means 3 hour 20 minutes

So, they meet at 8 : 20 p.m.

Easwar said:
1 decade ago

A train leaves a point A at 5 p.m. and reaches another point B a 11 p.m. Another train leaves point B at 7 p.m. and reaches point A at 10 p.m. At what time will the two trains meet?

8 : 15 p.m.

8 : 30 p.m.

8 : 20 p.m.

8 : 00 p.m.

can anyone solve this problem

8 : 15 p.m.

8 : 30 p.m.

8 : 20 p.m.

8 : 00 p.m.

can anyone solve this problem

Sathya said:
1 decade ago

Though the train B starts 1 hour late than train A, The speed of the train varies.

Amit Kr. SONI said:
1 decade ago

Hi Shri,

We can write here

(X-1) b'coz train 'B' starts travelling 1 hr later agains train 'A'.

So, At the end, train B will travel 1 hr short, out of full running time to meet each other. i.e 'X'

So, we can write total time for train 'B' = (X-1)

Thanks

We can write here

(X-1) b'coz train 'B' starts travelling 1 hr later agains train 'A'.

So, At the end, train B will travel 1 hr short, out of full running time to meet each other. i.e 'X'

So, we can write total time for train 'B' = (X-1)

Thanks

Shri said:
1 decade ago

Why (x-1) term is used ?

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