Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 30)
30.
Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
Answer: Option
Explanation:
Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x - 1) hours = 25(x - 1) km.
20x + 25(x - 1) = 110
45x = 135
x = 3.
So, they meet at 10 a.m.
Discussion:
92 comments Page 8 of 10.
Anith kumar said:
10 years ago
How we assume x=3 then how we get both meeting time at 10 please explain clearly to me.
Sumanth geras said:
10 years ago
Simple solution no formula, no concepts just common sense.
Let us consider first train it's speed is 20 km/hr.
So it covers 20 kms in 1 hour.
Starting from 7 am 1st train second train from 8 am to 9 am.
At 8 am it covers 20 km at 9 am it covers 25 km. 9 am it covers 40 km 10 am it covers 50 km.
10 am === 60 km.
So at 10 am total distance covered by two trains is 60+50=110 km.
Which is the actual distance of separation between two train hence they meet each other so simple.
Let us consider first train it's speed is 20 km/hr.
So it covers 20 kms in 1 hour.
Starting from 7 am 1st train second train from 8 am to 9 am.
At 8 am it covers 20 km at 9 am it covers 25 km. 9 am it covers 40 km 10 am it covers 50 km.
10 am === 60 km.
So at 10 am total distance covered by two trains is 60+50=110 km.
Which is the actual distance of separation between two train hence they meet each other so simple.
Mohit said:
1 decade ago
Let 't' b the time in hrs the two trains meet. Then distance traveled by 1st train is 20t and distance.
Traveled by 2nd train is 25 (t-1). Because 2nd train run after 1hr of 1st train.
Total distance = 110 km = 20t+25(t-1).
Solving we get t = 3hr. 7 a.m.+3hr = 10 a.m.
Traveled by 2nd train is 25 (t-1). Because 2nd train run after 1hr of 1st train.
Total distance = 110 km = 20t+25(t-1).
Solving we get t = 3hr. 7 a.m.+3hr = 10 a.m.
Arun said:
1 decade ago
@Chai.
Answer : 2.15 pm. Is this correct?
Answer : 2.15 pm. Is this correct?
Arun said:
1 decade ago
@Chai.
Sorry I will be confused. I got two answers by solving two different methods.
I got 2.15 pm and also I got 4.15 pm.
Sorry I will be confused. I got two answers by solving two different methods.
I got 2.15 pm and also I got 4.15 pm.
R v said:
1 decade ago
One train will cover 20 km in one hour.
Now the distance remaining is 90 km.
So time take is equal to 90/20+25 = 2 hours means will meet 2 hours after 8 am i.e. 10 am.
Now the distance remaining is 90 km.
So time take is equal to 90/20+25 = 2 hours means will meet 2 hours after 8 am i.e. 10 am.
Chai said:
1 decade ago
A and B are two stations 390 km a part. A train start from A at 10 AM and travels towards B at 65 kmph. Another train start from B at 11 AM and travels towards A at 35 kmph. At what time do they meet? Solve this problem.
Gokul said:
1 decade ago
How 20x + 25(x-1) = 110?
Buddhikawd said:
1 decade ago
A_________________110KM______________________B.
7.00 AM. 8.00 AM.
20 KMH. 25 KMh.
2nd train after 1 hour.
So 1st train gone to 20 km.
Because totally 110-20 = 90 km.
Now 20 kmh+25 kmh = 45 kmh.
90/45 = 2 hours.
Now we count 8.00 am+ 2 hours = 10.00 AM.
7.00 AM. 8.00 AM.
20 KMH. 25 KMh.
2nd train after 1 hour.
So 1st train gone to 20 km.
Because totally 110-20 = 90 km.
Now 20 kmh+25 kmh = 45 kmh.
90/45 = 2 hours.
Now we count 8.00 am+ 2 hours = 10.00 AM.
Suresh said:
1 decade ago
Hai @Poojitha.
x is the time taken, 20 is speed.
So Speed*Time = Distance.
For first train it is 20x. And as the second train started 1 hr later.
The time will be x-1. And distance = 25(x-1).
Since both the trains are yet to cover 110 km.
And travelling in opposite directions to meet each other and we have to calculate the meeting point of time. We have to add them. So,
It is 20x+25(x-1) = 110.
Hope it is clear now.
x is the time taken, 20 is speed.
So Speed*Time = Distance.
For first train it is 20x. And as the second train started 1 hr later.
The time will be x-1. And distance = 25(x-1).
Since both the trains are yet to cover 110 km.
And travelling in opposite directions to meet each other and we have to calculate the meeting point of time. We have to add them. So,
It is 20x+25(x-1) = 110.
Hope it is clear now.
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