Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 30)
30.
Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
Answer: Option
Explanation:
Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x - 1) hours = 25(x - 1) km.
20x + 25(x - 1) = 110
45x = 135
x = 3.
So, they meet at 10 a.m.
Discussion:
92 comments Page 5 of 10.
R v said:
1 decade ago
One train will cover 20 km in one hour.
Now the distance remaining is 90 km.
So time take is equal to 90/20+25 = 2 hours means will meet 2 hours after 8 am i.e. 10 am.
Now the distance remaining is 90 km.
So time take is equal to 90/20+25 = 2 hours means will meet 2 hours after 8 am i.e. 10 am.
Arun said:
1 decade ago
@Chai.
Answer : 2.15 pm. Is this correct?
Answer : 2.15 pm. Is this correct?
Arun said:
1 decade ago
@Chai.
Sorry I will be confused. I got two answers by solving two different methods.
I got 2.15 pm and also I got 4.15 pm.
Sorry I will be confused. I got two answers by solving two different methods.
I got 2.15 pm and also I got 4.15 pm.
Mohit said:
1 decade ago
Let 't' b the time in hrs the two trains meet. Then distance traveled by 1st train is 20t and distance.
Traveled by 2nd train is 25 (t-1). Because 2nd train run after 1hr of 1st train.
Total distance = 110 km = 20t+25(t-1).
Solving we get t = 3hr. 7 a.m.+3hr = 10 a.m.
Traveled by 2nd train is 25 (t-1). Because 2nd train run after 1hr of 1st train.
Total distance = 110 km = 20t+25(t-1).
Solving we get t = 3hr. 7 a.m.+3hr = 10 a.m.
Sumanth geras said:
10 years ago
Simple solution no formula, no concepts just common sense.
Let us consider first train it's speed is 20 km/hr.
So it covers 20 kms in 1 hour.
Starting from 7 am 1st train second train from 8 am to 9 am.
At 8 am it covers 20 km at 9 am it covers 25 km. 9 am it covers 40 km 10 am it covers 50 km.
10 am === 60 km.
So at 10 am total distance covered by two trains is 60+50=110 km.
Which is the actual distance of separation between two train hence they meet each other so simple.
Let us consider first train it's speed is 20 km/hr.
So it covers 20 kms in 1 hour.
Starting from 7 am 1st train second train from 8 am to 9 am.
At 8 am it covers 20 km at 9 am it covers 25 km. 9 am it covers 40 km 10 am it covers 50 km.
10 am === 60 km.
So at 10 am total distance covered by two trains is 60+50=110 km.
Which is the actual distance of separation between two train hence they meet each other so simple.
Anith kumar said:
10 years ago
How we assume x=3 then how we get both meeting time at 10 please explain clearly to me.
Hardik khatri said:
10 years ago
@Chai.
Why do we have to take the distance 390 when we add this covered by A after x hours and this covered by B after x-1 hours then why we equal it to 390 km?
Why do we have to take the distance 390 when we add this covered by A after x hours and this covered by B after x-1 hours then why we equal it to 390 km?
Raja said:
9 years ago
Here x=3 is answer how to convert into am/pm some other problem.
ANISH MISHRA said:
9 years ago
A train leaves P for Q; at the same time another train leaves Q for P. The trains meet after 6 hours, the train from P and Q having travelled 8 km per hour more than the other. If the distance from P and Q is 528 km, the speed of train from P and Q in km/hour is.
Please solve this?
Please solve this?
Naresh said:
9 years ago
The distance between two stations A and B is 110km.
1st Train starts at 7am at station A at a speed of 20kmph.
i.e. 1st train travels 20 kms in one hour.
Now The distance is 90kms.
2nd train stats at 8am at and travelling at a speed of 25kmph.
So, the Relative speed of two trains is 20 + 25 = 45kmph.
=> Time = Distance/Speed.
Time = 90/45 = 2hrs.
Requied answer is 8 A.M + 2hr =10 A.M.
1st Train starts at 7am at station A at a speed of 20kmph.
i.e. 1st train travels 20 kms in one hour.
Now The distance is 90kms.
2nd train stats at 8am at and travelling at a speed of 25kmph.
So, the Relative speed of two trains is 20 + 25 = 45kmph.
=> Time = Distance/Speed.
Time = 90/45 = 2hrs.
Requied answer is 8 A.M + 2hr =10 A.M.
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