Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 30)
30.
Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
9 a.m.
10 a.m.
10.30 a.m.
11 a.m.
Answer: Option
Explanation:

Suppose they meet x hours after 7 a.m.

Distance covered by A in x hours = 20x km.

Distance covered by B in (x - 1) hours = 25(x - 1) km.

Therefore 20x + 25(x - 1) = 110

=> 45x = 135

=> x = 3.

So, they meet at 10 a.m.

Discussion:
92 comments Page 4 of 10.

Ankita said:   9 years ago
Distance between two stations A and B is 100 km, two trains with speed 60 km/h and 40 km/h are running towards each other. What is the distance from station A where both trains will meet?

Can anyone find the answer?

Ayush said:   9 years ago
60 km as relative speed of both the trains is 100 km/hr and
distance = 100km.

Then time taken to meet = distance/speed(relative).
T = 100/100 = 1 hr

So the trains will meet each other after 1 hour so,
Distance covered by first train in 1 hour = 60km/hr * 1hr = 60 km,
Distance covered by second train in 1 hour = 40km/hr * 1hr = 40 km,
Therefore, the distance from station A where both trains will meet = 60km.

Sonic said:   9 years ago
Why it's taken x-1 but not x+1 because train 2 starts 1 hr later?

Dezosa said:   6 years ago
The speed of one train is twice the other so let,
Speed of 1st train is Y.
Speed of 2nd train is 2Y.

Then distance between point A and B is 6Y.

Suppose they meet x hours after 5 a.m.

Distance covered by 1st train in X hours = YX km.

Distance covered by B in (X - 2) hours = 2Y(X - 2) km.

Therefore YX + 2Y(X - 2) = 6Y.

=> YX + 2YX - 4Y = 6Y.

=> 3YX = 10Y.

=> X =10/3 (in hours).
=> X =10/3*60 (because converting into minutes).
=> X =200 minutes.
200 minutes means 3 hour 20 minutes.

So, They meet at 8 : 20 p.m.

Bhat ashraf said:   9 years ago
The difference of speeds of two trains P & Q is 20km/hr. Train P & Q start from points A & B & move towards each other. If the trains meet each other after 2 hr of the journey. What is the speed of the faster train?

Please answer it.

Swasti said:   9 years ago
How this 3 hr comes?

Mary said:   9 years ago
How to solve if they move in the same direction?

Basharat said:   9 years ago
This is based on relative speed.

If they are in opposite directions just add their speeds if they are in same directions subtract their speeds.

Sachin said:   9 years ago
Here
V1 =20 km/hr.
V2 = 25km/hr.
Time of meet they
= 110-20/20 + 25.
= 2hr.
Then 8+2 = 10am.

Chittaranjan said:   8 years ago
A_________________110KM______________________B.

7.00 AM. 8.00 AM.
20 KMH. 25 KMh.
2nd train after 1 hour.

So 1st train gone to 20 km.
Because totally 110-20 = 90 km.
Now 20 kmh+25 kmh = 45 kmh.
90/45 = 2 hours.
Now we count 8.00 am+ 2 hours = 10.00 AM.


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