Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 29)
29.
A train travelling at 48 kmph completely crosses another train having half its length and travelling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. The length of the platform is
400 m
450 m
560 m
600 m
Answer: Option
Explanation:

Let the length of the first train be x metres.

Then, the length of the second train is ( x ( metres.
2

Relative speed = (48 + 42) kmph = ( 90 x 5 ( m/sec = 25 m/sec.
18

Therefore [x + (x/2)] = 12 or 3x = 300     or     x = 200.
25 2

Therefore Length of first train = 200 m.

Let the length of platform be y metres.

Speed of the first train = ( 48 x 5 ( m/sec = 40 m/sec.
18 3

Therefore (200 + y) x 3 = 45
40

=> 600 + 3y = 1800

=> y = 400 m.

Discussion:
48 comments Page 4 of 5.

Syndhya said:   1 decade ago
Could anybody explain clearly. Please. I can't understand. Explain in a simple manner please.

Stuti said:   1 decade ago
I didn't understand any bit of the problem. Please some one do explain in an easy way :).

Raj said:   1 decade ago
Why should not we take length of second train as x and length of first train as 2x?

Suyash said:   7 years ago
Can anyone help me to get this step?

X+(x/2)/25=12==> 3X/2 =300 ==> X=200.

Chidu said:   9 years ago
Here, mentioning the 2nd train is not needed it is a straight forward question.

Dinesh said:   1 decade ago
Can any one explain why he took the 48 kmph in the length of the platform?

Sonu said:   1 decade ago
Can any one explain why should we consider second train length as "x/2"?

Monika said:   5 years ago
Not getting this clearly, please explain in detail.

Naveen said:   5 years ago
Why we didn't use the length of the second train?
(1)

Anu said:   10 years ago
Why he took first train length? Why can't second?


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