Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 29)
29.
A train travelling at 48 kmph completely crosses another train having half its length and travelling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. The length of the platform is
Answer: Option
Explanation:
Let the length of the first train be x metres.
| Then, the length of the second train is |  |
x |  |
metres. |
| 2 |
| Relative speed = (48 + 42) kmph = | |
90 x | 5 | |
m/sec = 25 m/sec. |
| 18 |
 |
[x + (x/2)] | = 12 or | 3x | = 300 or x = 200. |
| 25 | 2 |
Length of first train = 200 m.
Let the length of platform be y metres.
| Speed of the first train = | |
48 x | 5 | |
m/sec = | 40 | m/sec. |
| 18 | 3 |
| (200 + y) x |
3 | = 45 |
| 40 |
600 + 3y = 1800
y = 400 m.
Discussion:
48 comments Page 2 of 5.
Riya said:
7 years ago
Can anybody help me?
Why we are taking the first train speed for calculating the length of the platform?
Why we are taking the first train speed for calculating the length of the platform?
Shivani said:
7 years ago
As per knowledge, it is 200m.
Sai said:
7 years ago
Can anyone explain me in simple way?
Chandan.b said:
7 years ago
Can anybody explain this step for me?
x + (x/2)] = 12 or
3x = 300
or x = 200.
Therefore Length of first train = 200 m.
x + (x/2)] = 12 or
3x = 300
or x = 200.
Therefore Length of first train = 200 m.
Suyash said:
7 years ago
Can anyone help me to get this step?
X+(x/2)/25=12==> 3X/2 =300 ==> X=200.
X+(x/2)/25=12==> 3X/2 =300 ==> X=200.
Umang said:
8 years ago
@Reka.
Here in this question condition is given that only first train cross the railway platform in 45 seconds.
Here in this question condition is given that only first train cross the railway platform in 45 seconds.
Reka said:
8 years ago
Can anybody tell me why they have taken the 1st train to calculate the length of the platform, why not both the trains.
Borshon said:
8 years ago
Opposite direction,so speed of 2 train= 48+42=90, so length of 2 trains is =90*12*5/18=300. Given that 2nd train is half of the first train, so the length of first train= 200 m.
Now, length of platform =(200+x)18/48 * 5 = 45.
Solving, x = 400 m.
Now, length of platform =(200+x)18/48 * 5 = 45.
Solving, x = 400 m.
Suraj said:
9 years ago
@Lakhbir.
5/18 is used when converting kmph to mps.
18/5 is used when converting mps to kmph.
5/18 is used when converting kmph to mps.
18/5 is used when converting mps to kmph.
(1)
Rupesh said:
9 years ago
Can you explain me at relative speed?
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