Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 26)
26.
Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train?
23 m
23 2 m
9
27 7 m
9
29 m
Answer: Option
Explanation:

Relative speed = (40 - 20) km/hr = ( 20 x 5 ( m/sec = ( 50 ( m/sec.
18 9

Therefore Length of faster train = ( 50 x 5 ( m = 250 m = 27 7 m.
9 9 9

Discussion:
72 comments Page 7 of 8.

Grish said:   1 decade ago
The position of man is supposed to be ignore. It's a confusing element. Anyway the speed of slower train?

Divyansh said:   1 decade ago
When the question says this type that man is sitting but not tells the exact position the apply simple formula speed(Relative) = Distance/Time.

Ratnesh said:   1 decade ago
Hey to convert km/hr to m/s we have to use this conversion unit,
i.e 1000/(60*60)= 1000/3600.

Here 1 km = 1000 m and 1 hr = 60*60 =3600 seconds.
And when simplified it will give 5/18.

Hope your doubt about 18 would be clear now?

Subha said:   1 decade ago
According to the formula given here we can find the SUM OF LENGTH OF THE 2 TRAINS and not the length of the faster train which is asked in the question.

Sunny said:   1 decade ago
Here also the faster train crossing the slower train hence we get the length of 2 trains, not the faster train.

Sunny said:   1 decade ago
Please can anyone tell me the length of the slower train?

Bhavya said:   1 decade ago
Relative speed =40-20= 20 is okay after why we multiplied with 5/18, and wt is that 5/18?

Mancy said:   1 decade ago
Hi @Shweta.

We are taking relative speed because in the question direction of moving trains are mentioned so for calculating the length firstly we've to take relative speed.

Shwetha said:   1 decade ago
Hey can anyone tell me why we have to take relative speed. When question is regarding fast train length?

Nidhi said:   1 decade ago
Can anybody tell me that, then how can we calculate the length of the slower train?


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