Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 26)
26.
Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train?
Answer: Option
Explanation:
| Relative speed = (40 - 20) km/hr = |  |
20 x | 5 |  |
m/sec = | |
50 | |
m/sec. |
| 18 | 9 |
 Length of faster train = |
|
50 | x 5 | |
m = | 250 | m = 27 | 7 | m. |
| 9 | 9 | 9 |
Discussion:
72 comments Page 4 of 8.
Tatikonda Dinesh said:
6 years ago
How to came 27 7/9?
Anybody, Please explain.
Anybody, Please explain.
M.vishwa Mohawk reddy said:
6 years ago
How came 27 7/9? I am not getting, Please explain.
Rohit Parmar said:
6 years ago
How to simplify 250/9 to 27*7/9?
Please explain clearly.
Please explain clearly.
Shri said:
6 years ago
@Shital.
It is a mixed fraction method, 27 * 9 = 243.
243 + 7 = 250.
It is a mixed fraction method, 27 * 9 = 243.
243 + 7 = 250.
Ananth said:
6 years ago
Divide 250 by 9. The Remainder * Quotient/Divisor rule then follows.
G Rajesh said:
6 years ago
I think if they asked to find the length of the smaller train we have to use same formula as explained above in explaination box. We can assume that length of two trains are same.
Ram said:
1 decade ago
Just ignore second train(ie., slow train) and assume man is running with 20km/hr speed. Both are in same direction.
Relative speed = 40-20 = 20 kmph.
Relative speed = 40-20 = 20 kmph.
Mj pala said:
1 decade ago
If the question is to find the length of the slower train, then?
Suman CKP said:
1 decade ago
And Suppose someone ask the speed of slower train then what will be do? Not clear?
Wangchuk said:
1 decade ago
According to formula relative speed is added when two train are moving in opposite direction and is subtracted in same direction.
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