Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 19)
19.
A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is:
Answer: Option
Explanation:
Let the length of the train be x metres and its speed by y m/sec.
| Then, | x | = 15  y = |
x | . |
| y | 15 |
 |
x + 100 | = | x |
| 25 | 15 |
15(x + 100) = 25x
15x + 1500 = 25x
1500 = 10x
x = 150 m.
Discussion:
55 comments Page 5 of 6.
Gautam Kumar Ray said:
8 months ago
We know S = D/T,
for train S = D/15,
Now,
D/15 = (D+100)/25,
3D + 300 = 5D,
D = 150.
for train S = D/15,
Now,
D/15 = (D+100)/25,
3D + 300 = 5D,
D = 150.
(2)
Gautam said:
8 months ago
Let the length of the train = x.
Now,
(X+100)/25 = X/15,
Then, X = 150.
Now,
(X+100)/25 = X/15,
Then, X = 150.
(1)
Prabhakaran said:
2 decades ago
I can't understand step 2 mohanraj can you explain again clearly.
Sahil chabra said:
6 years ago
Can anyone explain the below step in detail?
(100+x) /25=x/15.
(100+x) /25=x/15.
(3)
Rajesh said:
2 decades ago
other way is select any option and solve for both case
Vaibhav said said:
8 years ago
I can't unable to understand it, please explain.
Pavan said:
2 decades ago
Why we take x/y=15 can you please explain me?
Gowtham said:
2 decades ago
Please explain the question in detail.
Rosy said:
7 years ago
Please cam someone explains me again?
Gugi said:
5 years ago
Explain the answer, please.
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