Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 18)
18.
A 300 metre long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
300 |  |
m/sec = | 50 | m/sec. |
| 18 | 3 |
Let the length of the platform be x metres.
| Then, | |
x + 300 | |
= | 50 |
| 39 | 3 |
3(x + 300) = 1950
x = 350 m.
Discussion:
39 comments Page 3 of 4.
Santosh Kumar said:
2 years ago
Distance = 300m,
Time = 18.
Speed = Distance/Time.
= 300/18,
= 50/3.
Time = 18.
Speed = Distance/Time.
= 300/18,
= 50/3.
Bhaskar said:
10 years ago
Why don't we add 39 seconds + 18 seconds as the train is travelling in the same direction?
Atique said:
1 decade ago
Why should I take 300/18 ? Why shouldn't I take 300/39 ?
Please give explanation.
Please give explanation.
Rahul said:
9 years ago
Difficult to understand this calculation.
Is there any shortcut method?
Is there any shortcut method?
Pooja said:
1 decade ago
Hey can you please help me I am not getting 3(x+300)/39=50/3?
Archana said:
8 years ago
How it's 350? I didn't understand please tell me the answer.
Hemanth said:
7 years ago
In this problem, speed is not given then how to take 300/18?
(1)
Akhila said:
7 years ago
A simple and Understandable explanation, Thanks. @Sundar.
Bibek Nandy said:
2 years ago
300/18 = 50/3.
50/3x39 = 50x13 = 650.
650-300 = 350.
50/3x39 = 50x13 = 650.
650-300 = 350.
(6)
Masud said:
8 years ago
@Koushik Roy.
300/18 m/s, it's the speed of train.
300/18 m/s, it's the speed of train.
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