Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 18)
18.
A 300 metre long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?
320 m
350 m
650 m
Data inadequate
Answer: Option
Explanation:

Speed = ( 300 ( m/sec = 50 m/sec.
18 3

Let the length of the platform be x metres.

Then, ( x + 300 ( = 50
39 3

=> 3(x + 300) = 1950

=> x = 350 m.

Discussion:
39 comments Page 3 of 4.

Rahul said:   9 years ago
Difficult to understand this calculation.

Is there any shortcut method?

Rishi said:   9 years ago
First, calculate a speed of the train.

Length = Speed * Time.

Then, S = L/T.

300/18 = 16.66 m/s.

Then, L = S * T.

(x + 300) = 16.66 * 39.

X = 350 m.

Vinayaka N said:   10 years ago
Can anyone explain?

Why don't we add 39 seconds + 18 seconds as the train is travelling in the same direction as like in other previous problems?

Bhaskar said:   10 years ago
Why don't we add 39 seconds + 18 seconds as the train is travelling in the same direction?

Vijaya said:   1 decade ago
Speed 50/3 is correct. Because platform has a length. But pole doesnt. Its only a point that the train crossed. So the distance covered when it crosses the pole is just the train's length.

That is 300 metres. So the train moves at a speed of 300 metres per 18 seconds. Speed is 300/18. Hence 50/3.

Pooja said:   1 decade ago
How 50/3 is coming?

Pooja said:   1 decade ago
Hey can you please help me I am not getting 3(x+300)/39=50/3?

Ramesh said:   1 decade ago
How that 50/3 is coming?

Ahaugis said:   1 decade ago
Question does not specify average speed or constant speed. Acceleration is required too answer the question correctly. That means [D] is correct.

Waqas said:   1 decade ago
Hai dear sir, I am very confuse please help me explain that how we will measure the speed in detail with example?


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