Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 4)
4.
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
1 : 3
3 : 2
3 : 4
None of these
Answer: Option
Explanation:

Let the speeds of the two trains be x m/sec and y m/sec respectively.

Then, length of the first train = 27x metres,

and length of the second train = 17y metres.

27x + 17y = 23
x+ y

27x + 17y = 23x + 23y

4x = 6y

x = 3 .
y 2

Discussion:
239 comments Page 3 of 24.

ARUN said:   11 months ago
I do not understand this. Please explain to me.
(12)

Ebe said:   5 years ago
I have a small doubt regarding the formula.

In the question, they have said to find the ratio of speed. Not the ratio of time.

So aren't we supposed to modify the formula accordingly? Please someone explain.
(11)

Dripta Majumdar said:   1 year ago
Why is the length of the platform not taken into consideration? Anyone, please explain to me.
(11)

Poornima said:   2 decades ago
Let me explain in detail if anyone still not understood yet.

Please remember the formula for finding speed. Speed = Distance/Time.
Therefore, Distance = Speed x Time.

If a train crosses a man/pole/post/tree in T seconds, and speed of the train is S m/s, then

Then, the Length of the Train = (Speed x Time) = ST metres.

Note: Here, the distance traveled by train in T seconds at the Speed of S m/s is equal to the length of the train.

Now, lets come to the given problem.

Let speed of the first train = X.
Time taken taken by the first train to cross a man = 27 seconds.
Therefore, Length of the first train = Speed x Time = X x 27 = 27X metres.

Let speed of the second train = Y.
Time taken taken by the second train to cross a man = 17 seconds.
Therefore, Length of the second train = 17Y metres.

Important Formula:
If two trains of length a metres and b metres are moving in opposite directions at u m/s and v m/s, then:
The time taken by the trains to cross each other = (a + b) / (u + v) sec.


Given that, (a + b) / (u + v) = 23 seconds.

Here, a = 27X, b = 17Y and u = X, v = Y.

Therefore, (27X + 17Y)/(X + Y) = 23.

=> 27X + 17Y = 23X + 23Y

=> 4X = 6Y

=> X/Y = 6/4 = 3/2

=> X : Y = 3 : 2.
(9)

Nishitha said:   5 years ago
Given data:
t1=27 sec t2=17 sec
S=d/t,d=s * t.

d is consider as l,

l1=s1 * t1 =17 s1,l2 = s2* t2 =27 s2.

In question ,it clearly move in a opposite direction,so we have to use this formula->(l1+l2) /s1+s2.

Total time = (17s1+27s2)/s1 + s2,
23(s1+s2)= 17s1+27s2.

Rearrange it,
23s1-17s1=27s2-23s2,
6s1 = 4s2,
s1/s2 = 6/4=3/2.

So,the answer is 3:2
(8)

SAURABH PANDEY said:   2 years ago
Very well done. Thanks.
(8)

Karma said:   5 years ago
Isn't it like X/Y = 4/6?

How come in the above solution like X/Y 6/4=3:2.
X=4 and Y=6 isn't it?
(6)

Rohan said:   5 years ago
Can the ratio be 2:3? Anyone explain me, please.
(3)

DURAI said:   6 years ago
Short method is;

x person 27.
y person 17 add both distances and divide the total distance and multiple the same for both persons.

27+17/23 *2.
37/23 = 1.6 *2.
1.6*2.
Ans : 3.2.
(2)

Meenu said:   6 years ago
@Poornima.

Thank you for the explanation.
(2)


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