Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 4)
4.
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
Answer: Option
Explanation:
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
 |
27x + 17y | = 23 |
| x+ y |
27x + 17y = 23x + 23y
4x = 6y
| |
x | = | 3 | . |
| y | 2 |
Discussion:
237 comments Page 23 of 24.
Mahesh said:
6 years ago
27+3 = 30.
17+3 = 20.
30/20 = 3:2.
17+3 = 20.
30/20 = 3:2.
Sujata said:
1 decade ago
I agreee with Rohit calculation.
DilipReddy said:
8 years ago
Very clear explanations. Thanks.
Deb said:
7 years ago
We can solve by (27-23)/(23-17).
Sandeep said:
1 decade ago
It is simplest form. I'm happy.
Mahesh said:
8 years ago
860m, It consists of two cases.
Kripita said:
9 years ago
Very well explained. Thanks.
Yous said:
9 years ago
Why we should divide by x+y?
Kavya said:
7 years ago
Good answer, Thanks @Shyam.
Kartik said:
2 decades ago
Excellent explanation SRI.
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