Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 4)
4.
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
Answer: Option
Explanation:
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
![]() |
27x + 17y | = 23 |
x+ y |
27x + 17y = 23x + 23y
4x = 6y
![]() |
x | = | 3 | . |
y | 2 |
Discussion:
233 comments Page 21 of 24.
Vishnu said:
7 years ago
@Sudhan.
Isn't 27-17 = 10? How do you say it's 6?
Isn't 27-17 = 10? How do you say it's 6?
Priyesh verma said:
7 years ago
Two trains are moving in opposite direction with the speed of 36 k.m. /h and 54 k.m. /h cross each other in 12 seconds. The length of the 2nd train is half of the 1st train. The 1st train crosses a platform in 1. 30 minutes. Then what is the length of the platform? Please solve this.
Mahesh said:
7 years ago
860m, It consists of two cases.
DilipReddy said:
7 years ago
Very clear explanations. Thanks.
Naveen said:
7 years ago
Speed=(distance/time).
It rewritten as (distance/speed)=time.
Same case:
(relative distance/relative speed)=time
We understand the only thing how to calculate relative speed and relative distance,
Consider car A travel at x km/hr and car B travels at y km/hr
Both A and B travel in same direction means
Their relative speed=subtraction of two speed (x+y)km/hr.
Relative distance= (speed1*time1)-(s2+t2).
=27x-17y.
Here 27 and 17 are time1 and time2.
X and y are speed1 and speed2.
Case2:
CarA and carB travels opposite direction.
Relative speed= x+y(addition of speeds)
Relative distance=(speed1*time1)+(s2*t2)
So we get. = 27x+17y.
Finally (relative distance/relative speed)=time,
Therefore (27x+17y)/(x+y)=23,
Maybe my solutions help for you
It rewritten as (distance/speed)=time.
Same case:
(relative distance/relative speed)=time
We understand the only thing how to calculate relative speed and relative distance,
Consider car A travel at x km/hr and car B travels at y km/hr
Both A and B travel in same direction means
Their relative speed=subtraction of two speed (x+y)km/hr.
Relative distance= (speed1*time1)-(s2+t2).
=27x-17y.
Here 27 and 17 are time1 and time2.
X and y are speed1 and speed2.
Case2:
CarA and carB travels opposite direction.
Relative speed= x+y(addition of speeds)
Relative distance=(speed1*time1)+(s2*t2)
So we get. = 27x+17y.
Finally (relative distance/relative speed)=time,
Therefore (27x+17y)/(x+y)=23,
Maybe my solutions help for you
Harishankaran said:
7 years ago
@Priyesh Verma.
How can be a train, which taking time than the another, is consider as faster?
In the above example, the time taken by 1 train is 23sec and the other one is 17 sec but the ratio shows that 1train is faster than second.just imagine that length of the train is 54m.
Then,
54/27::54/17~=2:3.
How can be a train, which taking time than the another, is consider as faster?
In the above example, the time taken by 1 train is 23sec and the other one is 17 sec but the ratio shows that 1train is faster than second.just imagine that length of the train is 54m.
Then,
54/27::54/17~=2:3.
Shyam said:
7 years ago
T1=27-23=4,T2=23-17=6.
Speed=distance/time.
"Speed" inversely propotional to "time"
(S1/S2)=(T2/T1)=6/4=3/2,
S1:S2=3:2.
Speed=distance/time.
"Speed" inversely propotional to "time"
(S1/S2)=(T2/T1)=6/4=3/2,
S1:S2=3:2.
L.santhosh reddy said:
7 years ago
Here, they mentioned 23sec and17sec but in answer, they took it as 23m and 17m why?
Manish said:
7 years ago
27 and 17 are the length of the train and the speed of these train respectively x mtr/sec and y mtr/sec.
So 27x+17x are there relative speed of the train.
(27x+17y)/(x+y)=23.
Here 23 is given time in which the Cross each other's train after solving the above eq...
We get 4x=6y.
x/y=2/3 that's solved.
So 27x+17x are there relative speed of the train.
(27x+17y)/(x+y)=23.
Here 23 is given time in which the Cross each other's train after solving the above eq...
We get 4x=6y.
x/y=2/3 that's solved.
Shree said:
7 years ago
Thanks for explaining the answer. It's easy to understand the solution now.
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