Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 4)
4.
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
1 : 3
3 : 2
3 : 4
None of these
Answer: Option
Explanation:

Let the speeds of the two trains be x m/sec and y m/sec respectively.

Then, length of the first train = 27x metres,

and length of the second train = 17y metres.

27x + 17y = 23
x+ y

27x + 17y = 23x + 23y

4x = 6y

x = 3 .
y 2

Discussion:
233 comments Page 14 of 24.

Deepak said:   1 decade ago
@niveditha

Since both train crossing each other in 23s, so have to multiply 23 by sum of speed of both train.

Krishna said:   1 decade ago
If I divide speed of one train 27 divided by another its almost 1.5 can I choose 3:2. Is it a pure coincidence ?

Cherry said:   1 decade ago
Can any one say how does this length of the first and second trains are considered as 27x and 17y respectively?

Eshu said:   1 decade ago
Since both the trains are moving in opposite direction. To find total we have to add the sum of train length.

Ashfaq said:   8 years ago
Distance /time = speed.

but here in solution
distance /time = time (i.e 23 seconds )

How it is possible?

Samara said:   8 years ago
Let the distance of platform be x.

Then speed1= x/27-23 and speed2= x/23-17,
So, the ratio of speed is 3:2.

Shiv said:   4 years ago
Here is simple solution for this question.

When we take it as mixture;
23 - 17 = 6
27 - 23 = 4
6/4 i.e 3:2.
(46)

Raj said:   9 years ago
Short-cut : Alligation method.


27 17
23
6 4

= 6 : 4 means 3 : 2 => Answer.

Satish said:   1 decade ago
27x+17y
-------- = 23
x+y
27x+17y=23x+23y
27x-23x=23y-17y
4x=6y
3 x
- =- x:y= 3:2
2 y

Nayana said:   1 decade ago
Can anyone how we got 3/2 since I understood till 4x=6y after that I didn't get that division step.


Post your comments here:

Your comments will be displayed after verification.