Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 3)
3.
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Answer: Option
Explanation:
| Speed = |  |
45 x | 5 |  m/sec |
= | |
25 | m/sec. |
| 18 | 2 |
Time = 30 sec.
Let the length of bridge be x metres.
| Then, | 130 + x | = | 25 |
| 30 | 2 |
2(130 + x) = 750
x = 245 m.
Video Explanation: https://youtu.be/M_d8WufJWKc
Discussion:
247 comments Page 9 of 25.
Coolburn said:
1 decade ago
Hi, I had my own solustion on that
45 km/hr
1km = 1000m
1hr = 3600 sec
45 km/hr convert to metter
=45000 m
=3600 sec.
45000/3600
=12.5
Since 30 sec can cross the bridge
=12.5*30
=375-130
=245m
45 km/hr
1km = 1000m
1hr = 3600 sec
45 km/hr convert to metter
=45000 m
=3600 sec.
45000/3600
=12.5
Since 30 sec can cross the bridge
=12.5*30
=375-130
=245m
(1)
Unnamali said:
1 decade ago
I think there is any relation b/w train length and bridge length.
So we are adding the length of the train and bridge and also the train moves opposite to bridge.
Please help me it is correct or not.
So we are adding the length of the train and bridge and also the train moves opposite to bridge.
Please help me it is correct or not.
Kamal Jeet said:
9 years ago
Simple Solution!
First of All change 45 KM/HR = 45000 m/s.
Travelling in 60 sec = 45000/60 = 750.
Now for 30 sec = 750/2 = 375.
Last subtract train length = 375 - 130 = 245.
I hope, this helps you!
First of All change 45 KM/HR = 45000 m/s.
Travelling in 60 sec = 45000/60 = 750.
Now for 30 sec = 750/2 = 375.
Last subtract train length = 375 - 130 = 245.
I hope, this helps you!
Harry said:
9 years ago
Speed is 45km/hr
Let's make it to seconds.
(45/3600) * 1000,
=12.5 m in 1sec.
Now let's see it in 30 sec i.e 12.5 * 30 = 375.
So in 30 secs it travels 375 but trains length is 130.
375 - 130 = 245m.
Let's make it to seconds.
(45/3600) * 1000,
=12.5 m in 1sec.
Now let's see it in 30 sec i.e 12.5 * 30 = 375.
So in 30 secs it travels 375 but trains length is 130.
375 - 130 = 245m.
Sarvjeet said:
1 decade ago
Length of the train= 130.
Speed of the train = 45km/hr.
time=30sec.
lengthof bridge = x+length of train.
x+length of train = Speed of the train *time.
x+130=45*5/18*30.
x+130 =375
x=375-130
x=245
Speed of the train = 45km/hr.
time=30sec.
lengthof bridge = x+length of train.
x+length of train = Speed of the train *time.
x+130=45*5/18*30.
x+130 =375
x=375-130
x=245
Sohail Khan said:
1 decade ago
We know that:
Time = Distance/Speed.
Suppose length of the bridge is X mtr.
Length of the train is 130 mtr.
So total distance = 130+X.
30 = (130+X)/45*(5/18).
Then the value of X is 245 mtr.
Time = Distance/Speed.
Suppose length of the bridge is X mtr.
Length of the train is 130 mtr.
So total distance = 130+X.
30 = (130+X)/45*(5/18).
Then the value of X is 245 mtr.
(1)
Dileep kumar said:
1 decade ago
Distance = speed/time;
Let us bridge length = x say, train travelling distance = 130 m.
The total distance is = x+130;
Speed = 25/2;time = 30sec;
:: x+130 = (25/2) 30;
x = 375-130;
= 245.
Let us bridge length = x say, train travelling distance = 130 m.
The total distance is = x+130;
Speed = 25/2;time = 30sec;
:: x+130 = (25/2) 30;
x = 375-130;
= 245.
Emme Naresh said:
9 years ago
Distance = speed/time;.
Let us bridge length = x say, train travelling distance = 130 m.
The total distance is = x + 130,
Speed = 25/2; time = 30sec.
X + 130 = (25/2) 30,
X = 375 - 130 = 245.
Let us bridge length = x say, train travelling distance = 130 m.
The total distance is = x + 130,
Speed = 25/2; time = 30sec.
X + 130 = (25/2) 30,
X = 375 - 130 = 245.
Mohan said:
1 decade ago
This problem is very easy to solve
speed(v) of train=45km/hr
length of train(d)=130m
time(t)=30sec
d=v*t
d=(45*5/18)*30
d=(25/2)*30
d=375
length of bridge(x)=d-length of train
x=375-130
x=245m
speed(v) of train=45km/hr
length of train(d)=130m
time(t)=30sec
d=v*t
d=(45*5/18)*30
d=(25/2)*30
d=375
length of bridge(x)=d-length of train
x=375-130
x=245m
Naveen kumar said:
2 decades ago
Hi jose, by cross mulyiplication method it will come as
2(130 + x) = 25*30
then 2(130 + x) = 750
then (130+x)=750/2
then (130+x)=375
then x=375-130
then finally ength of the bridge is 245m.
2(130 + x) = 25*30
then 2(130 + x) = 750
then (130+x)=750/2
then (130+x)=375
then x=375-130
then finally ength of the bridge is 245m.
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