Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 3)
3.
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
200 m
225 m
245 m
250 m
Answer: Option
Explanation:

Speed = 45 x 5 m/sec = 25 m/sec.
18 2

Time = 30 sec.

Let the length of bridge be x metres.

Then, 130 + x = 25
30 2

2(130 + x) = 750

x = 245 m.

Video Explanation: https://youtu.be/M_d8WufJWKc

Discussion:
245 comments Page 5 of 25.

Sonik Salam said:   4 years ago
260+2x=750.
2x=750-260,
2x=490,
And x = 490/2 = 245m.
(1)

Sid said:   4 years ago
Why it is +x, it also be -x, right?
(1)

Deepak Sahoo said:   4 years ago
Thanks for explaining the answer @Fathima.
(1)

Uvitha said:   2 decades ago
Can you explain me in detail ?

Nusrat fathima said:   2 decades ago
Hi Uvitha,



Speed=25/2 m/sec



then we find the lenght of the bridge using the formula



distance/time = speed



where distance = length of train + x



Time = 30 sec & speed = 25/2



130 + x 25

------- = --

30 2


=> 245 m

Sai said:   2 decades ago
Hi all, i've solved this problem in anotha way

given,

time=30 sec and speed=45km i.e 45x5/18

so im finding the distance= time x speed = 30 x 225/18 = 375m

thus,the distance travelled by the train is 375m and the length given was 130m

so 375-130 = 245m

Now my question is..could someone insist me that the method followed by me is the right one?

Karthik said:   2 decades ago
Yes fathima you are write.

Nusrat Fathima said:   2 decades ago
Thanks karthik

Sai the method mentioned by u is also a right method to solve the above problem..... Good thinking.

Jose said:   2 decades ago
Hey how is possible to come ?

2(130 + x) = 750

x = 245 m.

please advice me

Naveen kumar said:   2 decades ago
Hi jose, by cross mulyiplication method it will come as
2(130 + x) = 25*30
then 2(130 + x) = 750
then (130+x)=750/2
then (130+x)=375
then x=375-130
then finally ength of the bridge is 245m.


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