Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 3)
3.
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Answer: Option
Explanation:
Speed = | ![]() |
45 x | 5 | ![]() |
= | ![]() |
25 | ![]() |
18 | 2 |
Time = 30 sec.
Let the length of bridge be x metres.
Then, | 130 + x | = | 25 |
30 | 2 |
2(130 + x) = 750
x = 245 m.
Video Explanation: https://youtu.be/M_d8WufJWKc
Discussion:
245 comments Page 5 of 25.
Sonik Salam said:
4 years ago
260+2x=750.
2x=750-260,
2x=490,
And x = 490/2 = 245m.
2x=750-260,
2x=490,
And x = 490/2 = 245m.
(1)
Sid said:
4 years ago
Why it is +x, it also be -x, right?
(1)
Deepak Sahoo said:
4 years ago
Thanks for explaining the answer @Fathima.
(1)
Uvitha said:
2 decades ago
Can you explain me in detail ?
Nusrat fathima said:
2 decades ago
Hi Uvitha,
Speed=25/2 m/sec
then we find the lenght of the bridge using the formula
distance/time = speed
where distance = length of train + x
Time = 30 sec & speed = 25/2
=> 245 m
Speed=25/2 m/sec
then we find the lenght of the bridge using the formula
distance/time = speed
where distance = length of train + x
Time = 30 sec & speed = 25/2
130 + x 25
------- = --
30 2
=> 245 m
Sai said:
2 decades ago
Hi all, i've solved this problem in anotha way
given,
time=30 sec and speed=45km i.e 45x5/18
so im finding the distance= time x speed = 30 x 225/18 = 375m
thus,the distance travelled by the train is 375m and the length given was 130m
so 375-130 = 245m
Now my question is..could someone insist me that the method followed by me is the right one?
given,
time=30 sec and speed=45km i.e 45x5/18
so im finding the distance= time x speed = 30 x 225/18 = 375m
thus,the distance travelled by the train is 375m and the length given was 130m
so 375-130 = 245m
Now my question is..could someone insist me that the method followed by me is the right one?
Karthik said:
2 decades ago
Yes fathima you are write.
Nusrat Fathima said:
2 decades ago
Thanks karthik
Sai the method mentioned by u is also a right method to solve the above problem..... Good thinking.
Sai the method mentioned by u is also a right method to solve the above problem..... Good thinking.
Jose said:
2 decades ago
Hey how is possible to come ?
2(130 + x) = 750
x = 245 m.
please advice me
2(130 + x) = 750
x = 245 m.
please advice me
Naveen kumar said:
2 decades ago
Hi jose, by cross mulyiplication method it will come as
2(130 + x) = 25*30
then 2(130 + x) = 750
then (130+x)=750/2
then (130+x)=375
then x=375-130
then finally ength of the bridge is 245m.
2(130 + x) = 25*30
then 2(130 + x) = 750
then (130+x)=750/2
then (130+x)=375
then x=375-130
then finally ength of the bridge is 245m.
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