Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 3)
3.
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
200 m
225 m
245 m
250 m
Answer: Option
Explanation:

Speed = 45 x 5 m/sec = 25 m/sec.
18 2

Time = 30 sec.

Let the length of bridge be x metres.

Then, 130 + x = 25
30 2

2(130 + x) = 750

x = 245 m.

Video Explanation: https://youtu.be/M_d8WufJWKc

Discussion:
245 comments Page 4 of 25.

DURAI said:   5 years ago
Well said, thanks @Coolburn.
(1)

Priyanka Priyadarshini Samal said:   5 years ago
We have to calculate speed.
Speed = 45*5/18=25/2 m/s.

Time is given t= 30 sec.
Let's find the length of the bridge,
Let the length of the bridge is X.

And whenever a train crosses the bridge then the total distance covered by the train is the length of the bridge +it's own length (train's length),

According to the motion's 1st law distance or displacement = speed *time.
X+130 =25/2*30.
2(X+130)=750.
2X+260= 750.
X= (750-260)/2= 245m.
(1)

Kaushik vinay said:   5 years ago
45*18/5 = 25/3.

Mahamud said:   5 years ago
Can you explain, How come25/2?

Kavya said:   6 years ago
D= S * T.

D = 45 * 5/18 * 30 = 375m,
375-130=245m.
(2)

Navin said:   6 years ago
How 25/2 came? Explain, please.

Sejarc said:   6 years ago
It's simple one.

The train goes on a speed of 12.5 m/sec (45km/hr). So it crosses 375m in 30 sec.

Simply, 375 m - length of the train (130 m) =245 m (length of the bridge) => answer.

Sathish said:   6 years ago
45 * (5÷18) = (Lb +130)/30.
Lb = 245 m.

Saikrishna said:   6 years ago
@Naveen Kumar,

That 2(130+x) = 750 come as,

2(130+x) = 750, then,
Multiply (130+x) with 2 = 260+2x = 750.
260+ 2x = 750 .
2x = 750 - 260.
2x = 490.

x= 490/2.
x= 245 meters.

You got it, this is simple way.

Nilesh said:   6 years ago
How will you get 25/2 from 45 * 5/18?


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