Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 3)
3.
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Answer: Option
Explanation:
Speed = | ![]() |
45 x | 5 | ![]() |
= | ![]() |
25 | ![]() |
18 | 2 |
Time = 30 sec.
Let the length of bridge be x metres.
Then, | 130 + x | = | 25 |
30 | 2 |
2(130 + x) = 750
x = 245 m.
Video Explanation: https://youtu.be/M_d8WufJWKc
Discussion:
245 comments Page 24 of 25.
Jagabandhu patra said:
1 decade ago
(45000/3600*30)-130 = 245.
(1)
Patel said:
8 years ago
Nice explanation @Rajesh.
Manoj Reddy said:
8 years ago
Nice explanation @Rajesh.
Mathsfobia said:
1 decade ago
Nice explanation survjt.
Sharmin said:
10 years ago
30 = 130+x/45*3.6 = 245.
Abd said:
8 years ago
How 750? Explain please.
Gaurav rana said:
9 years ago
Why 130 is added to it?
Ravi said:
7 years ago
How do you take 5/18?
A.srinivas said:
1 decade ago
(x+130)/30=(45*5)/18
Chithu said:
1 decade ago
Very useful methods.
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