Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 3)
3.
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Answer: Option
Explanation:
Speed = | ![]() |
45 x | 5 | ![]() |
= | ![]() |
25 | ![]() |
18 | 2 |
Time = 30 sec.
Let the length of bridge be x metres.
Then, | 130 + x | = | 25 |
30 | 2 |
2(130 + x) = 750
x = 245 m.
Video Explanation: https://youtu.be/M_d8WufJWKc
Discussion:
245 comments Page 23 of 25.
Prakash said:
3 years ago
We have to calculate speed.
Speed = 45*5/18=25/2 m/s.
Time is given t= 30 sec.
Let's find the length of the bridge,
Let the length of the bridge is X.
And whenever a train crosses the bridge then the total distance covered by the train is the length of the bridge it's own length (train's length).
According to the motion's 1st law distance or displacement = speed * time.
X + 130 = 25/2 * 30.
2(X + 130) =750.
2X + 260 = 750.
X = (750-260)/2= 245m.
Speed = 45*5/18=25/2 m/s.
Time is given t= 30 sec.
Let's find the length of the bridge,
Let the length of the bridge is X.
And whenever a train crosses the bridge then the total distance covered by the train is the length of the bridge it's own length (train's length).
According to the motion's 1st law distance or displacement = speed * time.
X + 130 = 25/2 * 30.
2(X + 130) =750.
2X + 260 = 750.
X = (750-260)/2= 245m.
(9)
WDL said:
3 years ago
Speed = 45*(5/18)=25/2 m/s.
Displacement = speed * time(here time is 30sec).
X + 130 = 25/2 * 30.
2(X + 130) =750.
2X + 260 = 750.
X = (750-260)/2= 245m.
Displacement = speed * time(here time is 30sec).
X + 130 = 25/2 * 30.
2(X + 130) =750.
2X + 260 = 750.
X = (750-260)/2= 245m.
(12)
Adaeze Thompson said:
3 years ago
How do you get 25/2? Explain, please.
(15)
Prakash said:
3 years ago
Why are you people adding the bridge distance?
If in case the bridge distance is lesser than the train distance, then how it will be calculated?
If in case the bridge distance is lesser than the train distance, then how it will be calculated?
(19)
Vaghela Milankumar said:
3 years ago
4.5x 5/18 = 12.5
12.5 x 30 = 375
375 - 130 = 245 ans.
12.5 x 30 = 375
375 - 130 = 245 ans.
(55)
Shah Sonu said:
2 years ago
Given TD = 130m, speed = 45km/h, Time = 30sec.
And Length of the Station = x.
speed = 45*5/18 .
=225/18.
So, the speed =25/2.
know the length of the station,
x + TD = speed * Time
x + 130 = 25/2 * 30
x + 130 = 12.5 * 30
x + 130 = 375.
x = 375 - 130,
Final x = 245.
The correct answer is option C.
And Length of the Station = x.
speed = 45*5/18 .
=225/18.
So, the speed =25/2.
know the length of the station,
x + TD = speed * Time
x + 130 = 25/2 * 30
x + 130 = 12.5 * 30
x + 130 = 375.
x = 375 - 130,
Final x = 245.
The correct answer is option C.
(28)
Kaviprema said:
2 years ago
Soln,
L.t -130m ,s -45km/hr ,t -30 sec
L.b - ?.
Let us assume length of the bridge as x,
D = s* t.
130 (l.t) + x(l.b) = 45 km/hr * 30 sec.
130 + x =45 * 5/18 m/ sec * 30 sec.
After solving we will get,
130 + x = 375,
x = 375 -130,
x = 245 m.
So, the length of the bridge is 245 m.
L.t -130m ,s -45km/hr ,t -30 sec
L.b - ?.
Let us assume length of the bridge as x,
D = s* t.
130 (l.t) + x(l.b) = 45 km/hr * 30 sec.
130 + x =45 * 5/18 m/ sec * 30 sec.
After solving we will get,
130 + x = 375,
x = 375 -130,
x = 245 m.
So, the length of the bridge is 245 m.
(28)
Rajesh said:
2 years ago
Why do we take 5/18, anyone, please Explain it?
(15)
Pavan Kumar Nagineni said:
2 years ago
To convert kilometres per hour (km/hr) to meters per second (m/sec), we use the conversion factor of 5/18. This conversion factor is derived from the relationship between kilometres and meters, as well as hours and seconds.
Here's the breakdown of the conversion:
1 kilometer = 1000 meters.
1 hour = 3600 seconds.
To convert km/hr to m/sec, we need to cancel out the kilometres and hours units while retaining the meters and seconds units. We can do this by multiplying the value in km/hr by a conversion factor that equates to 1.
To convert kilometres to meters, we multiply by 1000 (since 1 kilometre is equal to 1000 meters). This step cancels out the kilometres unit.
To convert hours to seconds, we multiply by 3600 (since 1 hour is equal to 3600 seconds). This step cancels out the hours unit.
So, the conversion factor becomes:
(1000 meters/1 kilometer) * (1 hour/3600 seconds)
Simplifying this expression gives us:
(1000/1) * (1/3600) = 1000/3600 = 5/18.
Hence, multiplying the value in km/hr by 5/18 will convert it to m/sec.
Here's the breakdown of the conversion:
1 kilometer = 1000 meters.
1 hour = 3600 seconds.
To convert km/hr to m/sec, we need to cancel out the kilometres and hours units while retaining the meters and seconds units. We can do this by multiplying the value in km/hr by a conversion factor that equates to 1.
To convert kilometres to meters, we multiply by 1000 (since 1 kilometre is equal to 1000 meters). This step cancels out the kilometres unit.
To convert hours to seconds, we multiply by 3600 (since 1 hour is equal to 3600 seconds). This step cancels out the hours unit.
So, the conversion factor becomes:
(1000 meters/1 kilometer) * (1 hour/3600 seconds)
Simplifying this expression gives us:
(1000/1) * (1/3600) = 1000/3600 = 5/18.
Hence, multiplying the value in km/hr by 5/18 will convert it to m/sec.
(18)
A SHRUJAN said:
2 years ago
Distance travelled by Train= length of bridge + length of the train
So, x + 130m.
Speed = 45km/hr = 45 * 5/18 = 25/2 m/s.
Distance = speed * time.
25/2 * 30,
= 245m.
So, x + 130m.
Speed = 45km/hr = 45 * 5/18 = 25/2 m/s.
Distance = speed * time.
25/2 * 30,
= 245m.
(64)
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