Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 3)
3.
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Answer: Option
Explanation:
Speed = | ![]() |
45 x | 5 | ![]() |
= | ![]() |
25 | ![]() |
18 | 2 |
Time = 30 sec.
Let the length of bridge be x metres.
Then, | 130 + x | = | 25 |
30 | 2 |
2(130 + x) = 750
x = 245 m.
Video Explanation: https://youtu.be/M_d8WufJWKc
Discussion:
247 comments Page 19 of 25.
Mano said:
1 decade ago
Your are right sushi.
Please help why we consider both lengths separately?
If the train is crossed 130m length in 10 sec it also covered length of bridge?
Why we are again consider the bridge length?
The train is already crossed the bridge in 10 sec. So the length of the bridge also covered.
Please help why we consider both lengths separately?
If the train is crossed 130m length in 10 sec it also covered length of bridge?
Why we are again consider the bridge length?
The train is already crossed the bridge in 10 sec. So the length of the bridge also covered.
Sushi said:
1 decade ago
HEY. I have a doubt. The length of train is already covering some length of the bridge. Then why we consider both lengths separately?
Karthick said:
1 decade ago
Formula is = (Length of the train + Length of the object)=(Speed of the train* Time of the object).
Chethan said:
1 decade ago
dis=len of train+bridge length(take a bridge as x)
130+x
speed=45km/hr=45*5/18=25/2
time=30sec
dis=speed*time
130+x=25/2*30
130+x=375
x=245m.
130+x
speed=45km/hr=45*5/18=25/2
time=30sec
dis=speed*time
130+x=25/2*30
130+x=375
x=245m.
Pulak said:
1 decade ago
Thanks Nil.
Nil said:
1 decade ago
Given:
1. Length of the train = 130 m
2. Speed of the train = 45 km/hr or (25/2) m/s
3. Time taken by the train to cross bridge = 30s
Find:
Length of the bridge = x meter
First, convert speed of the train from km/hr into m/s
So, speed of the train in m/s = [45*(5/18)] km/hr = (25/2) m/s
Now,
Distance(or length) = speed * time
But,Distance = (Length of the bridge + Length of the train) = speed * time
Distance = x + 130 = (25/2) * 30
x+130 = 375
x = 375 - 130
Length of the bridge = 245 m
1. Length of the train = 130 m
2. Speed of the train = 45 km/hr or (25/2) m/s
3. Time taken by the train to cross bridge = 30s
Find:
Length of the bridge = x meter
First, convert speed of the train from km/hr into m/s
So, speed of the train in m/s = [45*(5/18)] km/hr = (25/2) m/s
Now,
Distance(or length) = speed * time
But,Distance = (Length of the bridge + Length of the train) = speed * time
Distance = x + 130 = (25/2) * 30
x+130 = 375
x = 375 - 130
Length of the bridge = 245 m
Vikram said:
1 decade ago
Here, A Train 130meter long.
Speed of train=45km/hr=45000m/3600sec=12.5m/sec.
Within 30sec that train cross distance=12.5m/sec*30sec=375m/30sec.
So,Length of Bridge=Cross distance - length of Train
=375-130=245Meters.
Therefore , The Length of Train= 245Meters.
Speed of train=45km/hr=45000m/3600sec=12.5m/sec.
Within 30sec that train cross distance=12.5m/sec*30sec=375m/30sec.
So,Length of Bridge=Cross distance - length of Train
=375-130=245Meters.
Therefore , The Length of Train= 245Meters.
Mohan said:
1 decade ago
This problem is very easy to solve
speed(v) of train=45km/hr
length of train(d)=130m
time(t)=30sec
d=v*t
d=(45*5/18)*30
d=(25/2)*30
d=375
length of bridge(x)=d-length of train
x=375-130
x=245m
speed(v) of train=45km/hr
length of train(d)=130m
time(t)=30sec
d=v*t
d=(45*5/18)*30
d=(25/2)*30
d=375
length of bridge(x)=d-length of train
x=375-130
x=245m
Arundeep said:
1 decade ago
First of all arragne them in D= ST.
S = D/T or T = D/S.
S = D/T or T = D/S.
TheInternetGuy said:
1 decade ago
Is 45 km/hr relative speed between the bridge and the train?
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