Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 3)
3.
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Answer: Option
Explanation:
| Speed = |  |
45 x | 5 |  m/sec |
= | |
25 | m/sec. |
| 18 | 2 |
Time = 30 sec.
Let the length of bridge be x metres.
| Then, | 130 + x | = | 25 |
| 30 | 2 |
2(130 + x) = 750
x = 245 m.
Video Explanation: https://youtu.be/M_d8WufJWKc
Discussion:
249 comments Page 14 of 25.
Ayaz husain said:
1 decade ago
The role of 30 sec is, the first wheel of the train enters the bridge and the last wheel of the train leaves the other end point of the bridge in 30 sec. So the train has to train the bridge length plus the length of its own to cross the bridge.
Poonam Pipaliya said:
1 decade ago
What is role of 30 sec and from where it comes?
Dinesh said:
1 decade ago
As the train crosses, which means the train should start at the starting of bridge and completely leave the bridge.
So, (130+x+130) should be the distance traveled in 30 secs.
= (130+x+130)/30 = (45*5/18).
x = 115.
So, (130+x+130) should be the distance traveled in 30 secs.
= (130+x+130)/30 = (45*5/18).
x = 115.
Jitendra said:
1 decade ago
Can we try this way?
Length of train + Length of bridge = (Distance which train need to be cover in 30 sec).
(130 m + X)---(1)-X = Suppose length of bridge.
Speed of trains = 45 km/h speed given in km/h hence convert it in m/sec.
45*5/18 = 25/2 ----- (2).
From equation (1) and (2).
= 25/2 = (130+X)/30.
= 25*30 = 260+2X.
= 750-260 = 2X.
= 490/2 = X.
= 245 = X.
Hence length of bridge (X) will be 245 m.
Length of train + Length of bridge = (Distance which train need to be cover in 30 sec).
(130 m + X)---(1)-X = Suppose length of bridge.
Speed of trains = 45 km/h speed given in km/h hence convert it in m/sec.
45*5/18 = 25/2 ----- (2).
From equation (1) and (2).
= 25/2 = (130+X)/30.
= 25*30 = 260+2X.
= 750-260 = 2X.
= 490/2 = X.
= 245 = X.
Hence length of bridge (X) will be 245 m.
Pradnya said:
1 decade ago
I can't understand your answer please explain.
Shashi said:
1 decade ago
We can solve by using formula also @Anusha.
Anusha said:
1 decade ago
Hi friends I did in a different way:
Let the length of train b = 130.
Let the length of bridge b = x.
Therefore distance = x + 130.
Time = 30 sec.
S = 45 km/h = 45*5/18 = 25/2 m/s.
So, in this case distance = 375 m.
So, d = x + 130 substituting the value of d (distance).
We get 375 - 130 = x.
X = 245 m.
Let the length of train b = 130.
Let the length of bridge b = x.
Therefore distance = x + 130.
Time = 30 sec.
S = 45 km/h = 45*5/18 = 25/2 m/s.
So, in this case distance = 375 m.
So, d = x + 130 substituting the value of d (distance).
We get 375 - 130 = x.
X = 245 m.
Madan said:
1 decade ago
45*5/18 = 12.5.
12.5*30 = 375.
375-130 = 245.
12.5*30 = 375.
375-130 = 245.
Bala said:
1 decade ago
45*5/18 = 12.5.
12.5*30 = 375.
375-130 = 245.
12.5*30 = 375.
375-130 = 245.
Deep said:
1 decade ago
Easy method is by using time and distance formula.
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