Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 3)
3.
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Answer: Option
Explanation:
Speed = | ![]() |
45 x | 5 | ![]() |
= | ![]() |
25 | ![]() |
18 | 2 |
Time = 30 sec.
Let the length of bridge be x metres.
Then, | 130 + x | = | 25 |
30 | 2 |
2(130 + x) = 750
x = 245 m.
Video Explanation: https://youtu.be/M_d8WufJWKc
Discussion:
247 comments Page 13 of 25.
Sushi said:
1 decade ago
HEY. I have a doubt. The length of train is already covering some length of the bridge. Then why we consider both lengths separately?
Monika said:
1 decade ago
You can do this without any variable:
45 km/hr*5/18 = 25/2 m/s.
Total distance = 25/2*30 = 375.
Length of bridge = 375-130 = 245m.
45 km/hr*5/18 = 25/2 m/s.
Total distance = 25/2*30 = 375.
Length of bridge = 375-130 = 245m.
Santosh said:
9 years ago
No, WRONG ANSWER.
The correct answer is 115M.
X + 0.260km = 45 * 30/(60 * 60),
X + 0.26 = 0.375,
=> X= 0.115 KM = 115METERS.
The correct answer is 115M.
X + 0.260km = 45 * 30/(60 * 60),
X + 0.26 = 0.375,
=> X= 0.115 KM = 115METERS.
Atul said:
1 decade ago
Plz give me trick to solve to this. Bcz compny gives 1 minute /question and question is so lengthy, then how can I mange my time.
Abhi singh said:
7 years ago
So,
45 * 5/18 = 25/2 = 12.5.
Speed = 12.5,
Distance = time * speed = 30 * 12.5 = 375.
130+x = 375,
x = 375-130,
x = 245m/s.
45 * 5/18 = 25/2 = 12.5.
Speed = 12.5,
Distance = time * speed = 30 * 12.5 = 375.
130+x = 375,
x = 375-130,
x = 245m/s.
ARYAN said:
7 years ago
Length of the train = 130m.
speed =45km/h so, 45/3.6=12.5.
12.5*time=12.5*30=375m.
length of the bridge = [375-130] = 245m ANS.
speed =45km/h so, 45/3.6=12.5.
12.5*time=12.5*30=375m.
length of the bridge = [375-130] = 245m ANS.
(1)
Amit said:
9 years ago
Here, v = 45 km/hr = 45 * (1000/3600) = 25/2 m/s.
T = 30s.
S = vt = (25/2) * 30 = 375 m.
Now, L = 375 - 130 = 245 m (Ans).
T = 30s.
S = vt = (25/2) * 30 = 375 m.
Now, L = 375 - 130 = 245 m (Ans).
Dumpati Mahesh said:
1 decade ago
Here we should consider as per the problem that, Train is passing only one time through the bridge. So 130+B.L. Only sanjay.
Nattu said:
2 decades ago
But crossing chould mean the whole train should be off the bridge right? So why should we subtract the length of the train?
Sasidhar nrit said:
7 years ago
45 km/hr.
45000/60min = 750m /min.
travelling 750m per minute,
750m/30sec = 375m,
than 375m-130m = 245m.
Is this correct?
45000/60min = 750m /min.
travelling 750m per minute,
750m/30sec = 375m,
than 375m-130m = 245m.
Is this correct?
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