Aptitude - Problems on Numbers - Discussion
Discussion Forum : Problems on Numbers - General Questions (Q.No. 4)
4.
The difference between a two-digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1 : 2 ?
Answer: Option
Explanation:
Since the number is greater than the number obtained on reversing the digits, so the ten's digit is greater than the unit's digit.
Let ten's and unit's digits be 2x and x respectively.
Then, (10 x 2x + x) - (10x + 2x) = 36
9x = 36
x = 4.
Required difference = (2x + x) - (2x - x) = 2x = 8.
Discussion:
45 comments Page 4 of 5.
Nagendra said:
1 decade ago
Once u find x then try this method to get the answer
21X-12X
21(4)-12(4)
84-48
that means the two number are 84 and 48..
now we have to take the sum of one no and the difference of other no.. according to question sum of digits and difference of digits
that is
48=4+8=12(sum of digits)
84=8-4=4(diff of digits)
now the difference of these two answer
12-4=8
Hence the answer is 8.
21X-12X
21(4)-12(4)
84-48
that means the two number are 84 and 48..
now we have to take the sum of one no and the difference of other no.. according to question sum of digits and difference of digits
that is
48=4+8=12(sum of digits)
84=8-4=4(diff of digits)
now the difference of these two answer
12-4=8
Hence the answer is 8.
Shalini said:
1 decade ago
Why are we choosing 2x?
Mitali said:
1 decade ago
Here we have
The difference between a two-digit number and the number obtained by interchanging the digits is 36
let a,b be 2 numbers
so, a-b=36
ratio between the digits of the number is 1 : 2
let x,y be d digits of a number
x/y=1/2
so, y=2x
now a must be greater than b
here we can see y is greater than x
here
for a => y is ten's digit n x is unit's
for b => x is ten's digit n y is unit's
so (10y+x)-(10x+y)=36
(10*(2x)+x)-(10x + 2x)=36
(21x)-(12x)=36
9x=36
x=4
(y+x)-(y-x)=(x+2x)-(2x-x)=2x=8
The difference between a two-digit number and the number obtained by interchanging the digits is 36
let a,b be 2 numbers
so, a-b=36
ratio between the digits of the number is 1 : 2
let x,y be d digits of a number
x/y=1/2
so, y=2x
now a must be greater than b
here we can see y is greater than x
here
for a => y is ten's digit n x is unit's
for b => x is ten's digit n y is unit's
so (10y+x)-(10x+y)=36
(10*(2x)+x)-(10x + 2x)=36
(21x)-(12x)=36
9x=36
x=4
(y+x)-(y-x)=(x+2x)-(2x-x)=2x=8
Virendra said:
1 decade ago
In question diff is given i.e. 36 and ratio is 1:2
We just find out such a pair without calculating.
We just find out such a pair without calculating.
Ranjeet said:
1 decade ago
Mitali: Good Explanation from you, thanks.
Kcs said:
1 decade ago
Two digits x&y
x:y=1:2
x=k
y=2k
two numbers 10x+y&10y+x
10x+y=10k+2k=12k
10y+x=20k+k=21k
diff=9k=36
k=4
numbers 12k=48
21k=84
sum of dgts=12
diff of dgts=4
ans=sum-diff=8
x:y=1:2
x=k
y=2k
two numbers 10x+y&10y+x
10x+y=10k+2k=12k
10y+x=20k+k=21k
diff=9k=36
k=4
numbers 12k=48
21k=84
sum of dgts=12
diff of dgts=4
ans=sum-diff=8
AMIT RANJAN said:
8 years ago
Suppose we take two nos as X & Y,
then, 10X+Y-10Y-X=36
=> 9X-9y=36 =>X-Y=4 ---> (A)
Given, X:Y = 1:2 => X = Y/2
Now from eq (A) , Y/2 - Y = 4 => -Y/2 = 4 => Y= -8 ---> (B)
A/Q, (X + Y) - (X - Y) = ?
=> X + Y - X + Y= ? => 2Y = ? ---> (C)
So from (B) putting the value of 'Y' in (C),
2Y = 2 * (-8) = -16 ANS.
then, 10X+Y-10Y-X=36
=> 9X-9y=36 =>X-Y=4 ---> (A)
Given, X:Y = 1:2 => X = Y/2
Now from eq (A) , Y/2 - Y = 4 => -Y/2 = 4 => Y= -8 ---> (B)
A/Q, (X + Y) - (X - Y) = ?
=> X + Y - X + Y= ? => 2Y = ? ---> (C)
So from (B) putting the value of 'Y' in (C),
2Y = 2 * (-8) = -16 ANS.
Leopard said:
1 decade ago
Let's the digits are x & y.
The ratio between them is x:y = 1:2.
So y=2x.
Hence y is ten digit no.
According to statement,
(10y+x)-(10x+y) = 36.
(10*2x+x)-(10x+2x) = 36.
21x-12x = 36.
9x = 36.
x = 4..
(y+x)-(y-x) = (2x+4)-(2x-4).
= (8+4)-(8-4).
= 12-4 = 8.
The ratio between them is x:y = 1:2.
So y=2x.
Hence y is ten digit no.
According to statement,
(10y+x)-(10x+y) = 36.
(10*2x+x)-(10x+2x) = 36.
21x-12x = 36.
9x = 36.
x = 4..
(y+x)-(y-x) = (2x+4)-(2x-4).
= (8+4)-(8-4).
= 12-4 = 8.
Deepak said:
1 decade ago
In the first condition, we get,
10x+y-(10y-x) = 36.
So, 9x-9y = 36.
By solving this we get x-y = 4. Thats all.
10x+y-(10y-x) = 36.
So, 9x-9y = 36.
By solving this we get x-y = 4. Thats all.
Priya said:
1 decade ago
Can anyone explain why do we take (y+x)-(y-x) in the last step rather than 10x+y-(10y-x) ?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers