Aptitude - Problems on Numbers - Discussion
Discussion Forum : Problems on Numbers - General Questions (Q.No. 4)
4.
The difference between a two-digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1 : 2 ?
Answer: Option
Explanation:
Since the number is greater than the number obtained on reversing the digits, so the ten's digit is greater than the unit's digit.
Let ten's and unit's digits be 2x and x respectively.
Then, (10 x 2x + x) - (10x + 2x) = 36
9x = 36
x = 4.
Required difference = (2x + x) - (2x - x) = 2x = 8.
Discussion:
45 comments Page 4 of 5.
Sarita said:
7 years ago
Thank you for the answer @Anju.
Sakshi said:
7 years ago
Thanks for the explanation @KCS.
Aaff said:
6 years ago
Thank you for the answer @Anusha.
Harshit said:
6 years ago
Correct answer should be 16. Ten's digit is X and Unit digit is 2X as the ratio given is 1:2 and not 2:1.
Vamsikrishnareddy said:
6 years ago
I am not getting this, please anyone explain me in detail.
Kolkata said:
6 years ago
I am not understanding it, please someone explain me.
(1)
Chitta meher said:
5 years ago
How come 10 here? Please explain.
Karthik said:
5 years ago
X is in units position and why is in ten's position. So the answer should be 16.
Md Parvez Islam said:
5 years ago
Thanks @Chinnadurai.
(1)
Sivasankaran said:
5 years ago
The given number is 36 which is +ve So the original number should be greater
Ex:
If ab is two-digit number b is in unit place and a is in 10th place (.etc..hundreds, tens, units)
Now the given ratio is 1:2 says that the ratio between 10s or 1s
The first number must greater than the reverse digit number.
So we give 2x in 10th place in the first number.
(Number)(10*2x+x)-(Reverse no-Small)(10x+2x)=36.
By solving X=4.
Then they said to find the sum and diff of number.
Ans=(2x+x)-(2x-x).
By solving;
We get the Ans is 8.
Ex:
If ab is two-digit number b is in unit place and a is in 10th place (.etc..hundreds, tens, units)
Now the given ratio is 1:2 says that the ratio between 10s or 1s
The first number must greater than the reverse digit number.
So we give 2x in 10th place in the first number.
(Number)(10*2x+x)-(Reverse no-Small)(10x+2x)=36.
By solving X=4.
Then they said to find the sum and diff of number.
Ans=(2x+x)-(2x-x).
By solving;
We get the Ans is 8.
(4)
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