Aptitude - Problems on Numbers - Discussion
Discussion Forum : Problems on Numbers - General Questions (Q.No. 4)
4.
The difference between a two-digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1 : 2 ?
Answer: Option
Explanation:
Since the number is greater than the number obtained on reversing the digits, so the ten's digit is greater than the unit's digit.
Let ten's and unit's digits be 2x and x respectively.
Then, (10 x 2x + x) - (10x + 2x) = 36
9x = 36
x = 4.
Required difference = (2x + x) - (2x - x) = 2x = 8.
Discussion:
45 comments Page 3 of 5.
Rishitha said:
9 years ago
Can anyone explain what happens after 12k = 48 and 21k = 84?
After we do this how do we get the final answer?
After we do this how do we get the final answer?
Aditrya tiwari said:
9 years ago
Consider no is 10x + y.
Then according to first condition (10x + y) - (10y + x) = 36.
On solving this we get, (x - y) = 4.
In, the last condition they give, y/x = 1/2.
By solving both above equations we get y = 4.
They ask the value for,(10x + y) - (10x - y).
Which is equal to 2y.
Put the value of y.
We get final value = 8.
Then according to first condition (10x + y) - (10y + x) = 36.
On solving this we get, (x - y) = 4.
In, the last condition they give, y/x = 1/2.
By solving both above equations we get y = 4.
They ask the value for,(10x + y) - (10x - y).
Which is equal to 2y.
Put the value of y.
We get final value = 8.
(3)
Rajesh jangid said:
10 years ago
Hi can anyone explain when to take 2x and x and when 10x+y-10y-x?
Jonsihay said:
10 years ago
The Problem should be re-stated specially on the aspect of the ratio.
It should "NOT JUST BE" 'if the ratio between the digits of the number is 1:2. But it should be restated as 'if the ratio between the unit's and ten's digits of the number is 1:2.
Then if that's ok, I think reliably be solvable!
It should "NOT JUST BE" 'if the ratio between the digits of the number is 1:2. But it should be restated as 'if the ratio between the unit's and ten's digits of the number is 1:2.
Then if that's ok, I think reliably be solvable!
(1)
S.prema said:
1 decade ago
Thanks for the explanation.
Chinnadurai said:
1 decade ago
Let digit at 10th place X and unit place Y.
From the question:
10X+Y-(10Y+X) = 36.
So, 10X-X+Y-10Y = 36.
= 9X-9Y = 36.
= X-Y = 4.
From question Ratio is 1x:2x.
Difference between the ratio 1x.
So 1x = 4 and 2x = 8. Sum and difference of these two 12, 4 respectively. Then difference between these two 8. Got answer.
From the question:
10X+Y-(10Y+X) = 36.
So, 10X-X+Y-10Y = 36.
= 9X-9Y = 36.
= X-Y = 4.
From question Ratio is 1x:2x.
Difference between the ratio 1x.
So 1x = 4 and 2x = 8. Sum and difference of these two 12, 4 respectively. Then difference between these two 8. Got answer.
(3)
Bhavna said:
1 decade ago
Assume the 2 digit number be 84 and by interchanging the digits we get 48.
Difference 84-48 = 36.
Sum = 4+8= 12.
Difference = 8-4 = 4.
Difference between sum & diff = 12-4 = 8.
Difference 84-48 = 36.
Sum = 4+8= 12.
Difference = 8-4 = 4.
Difference between sum & diff = 12-4 = 8.
Manu said:
1 decade ago
Why are you taking (10*2x+x) - (10+2x) = 36? Please explain it.
Pooja said:
1 decade ago
Hello Friends,
Suppose x & y two digits and the ratio b/w the digits of the number is 1:2
Therefor, x:y = 1:2
So, y = 2x ..........equation 1.
Hence, y is in ten's position and x is in unit place.
According to the question,
(10y + x) - (10x + y) = 36
From equation 1, we get y = 2x
(10*2x + x ) - (10x + 2x) = 36
(20x + x) - (12x) = 36
21x - 12x = 36
9x = 36
x = 4 ........... equation 2.
Now putting the value of x in equation 1.
y = 2*4
y = 8
Sum and the difference of the digits of the number (x + y) & (x - y) respectively.
According to question,
Difference between (x + y) & (x - y).
= (y+ x) - (y - x) ............. equation 3.
Putting the value of x = 4 & y = 8 in the above equation.
We get,
= (8 + 4) - (8 - 4).
= 12 - 4.
= 8.
Suppose x & y two digits and the ratio b/w the digits of the number is 1:2
Therefor, x:y = 1:2
So, y = 2x ..........equation 1.
Hence, y is in ten's position and x is in unit place.
According to the question,
(10y + x) - (10x + y) = 36
From equation 1, we get y = 2x
(10*2x + x ) - (10x + 2x) = 36
(20x + x) - (12x) = 36
21x - 12x = 36
9x = 36
x = 4 ........... equation 2.
Now putting the value of x in equation 1.
y = 2*4
y = 8
Sum and the difference of the digits of the number (x + y) & (x - y) respectively.
According to question,
Difference between (x + y) & (x - y).
= (y+ x) - (y - x) ............. equation 3.
Putting the value of x = 4 & y = 8 in the above equation.
We get,
= (8 + 4) - (8 - 4).
= 12 - 4.
= 8.
(2)
Priya said:
1 decade ago
Can anyone explain why do we take (y+x)-(y-x) in the last step rather than 10x+y-(10y-x) ?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers