Aptitude - Problems on Numbers - Discussion
Discussion Forum : Problems on Numbers - General Questions (Q.No. 4)
4.
The difference between a two-digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1 : 2 ?
Answer: Option
Explanation:
Since the number is greater than the number obtained on reversing the digits, so the ten's digit is greater than the unit's digit.
Let ten's and unit's digits be 2x and x respectively.
Then, (10 x 2x + x) - (10x + 2x) = 36
9x = 36
x = 4.
Required difference = (2x + x) - (2x - x) = 2x = 8.
Discussion:
45 comments Page 2 of 5.
Kolkata said:
5 years ago
I am not understanding it, please someone explain me.
(1)
Ramya said:
1 decade ago
Hi I could not understand this problem. Can anyone explain this more clearly please?
(1)
Jonsihay said:
9 years ago
The Problem should be re-stated specially on the aspect of the ratio.
It should "NOT JUST BE" 'if the ratio between the digits of the number is 1:2. But it should be restated as 'if the ratio between the unit's and ten's digits of the number is 1:2.
Then if that's ok, I think reliably be solvable!
It should "NOT JUST BE" 'if the ratio between the digits of the number is 1:2. But it should be restated as 'if the ratio between the unit's and ten's digits of the number is 1:2.
Then if that's ok, I think reliably be solvable!
(1)
Pooja said:
1 decade ago
Hello Friends,
Suppose x & y two digits and the ratio b/w the digits of the number is 1:2
Therefor, x:y = 1:2
So, y = 2x ..........equation 1.
Hence, y is in ten's position and x is in unit place.
According to the question,
(10y + x) - (10x + y) = 36
From equation 1, we get y = 2x
(10*2x + x ) - (10x + 2x) = 36
(20x + x) - (12x) = 36
21x - 12x = 36
9x = 36
x = 4 ........... equation 2.
Now putting the value of x in equation 1.
y = 2*4
y = 8
Sum and the difference of the digits of the number (x + y) & (x - y) respectively.
According to question,
Difference between (x + y) & (x - y).
= (y+ x) - (y - x) ............. equation 3.
Putting the value of x = 4 & y = 8 in the above equation.
We get,
= (8 + 4) - (8 - 4).
= 12 - 4.
= 8.
Suppose x & y two digits and the ratio b/w the digits of the number is 1:2
Therefor, x:y = 1:2
So, y = 2x ..........equation 1.
Hence, y is in ten's position and x is in unit place.
According to the question,
(10y + x) - (10x + y) = 36
From equation 1, we get y = 2x
(10*2x + x ) - (10x + 2x) = 36
(20x + x) - (12x) = 36
21x - 12x = 36
9x = 36
x = 4 ........... equation 2.
Now putting the value of x in equation 1.
y = 2*4
y = 8
Sum and the difference of the digits of the number (x + y) & (x - y) respectively.
According to question,
Difference between (x + y) & (x - y).
= (y+ x) - (y - x) ............. equation 3.
Putting the value of x = 4 & y = 8 in the above equation.
We get,
= (8 + 4) - (8 - 4).
= 12 - 4.
= 8.
(1)
Md Parvez Islam said:
4 years ago
Thanks @Chinnadurai.
(1)
Sravanthi said:
1 decade ago
Hi I can't understand this problem. Any more explnation please.
(1)
Sikha said:
1 decade ago
It can't b (x+y) - (x-y).
Rather it could be (10x +y) - (10y + x).
Rather it could be (10x +y) - (10y + x).
(1)
Vamsikrishnareddy said:
5 years ago
I am not getting this, please anyone explain me in detail.
Harshit said:
6 years ago
Correct answer should be 16. Ten's digit is X and Unit digit is 2X as the ratio given is 1:2 and not 2:1.
Rajesh jangid said:
9 years ago
Hi can anyone explain when to take 2x and x and when 10x+y-10y-x?
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