Aptitude - Problems on Numbers - Discussion
Discussion Forum : Problems on Numbers - General Questions (Q.No. 12)
12.
The product of two numbers is 120 and the sum of their squares is 289. The sum of the number is:
Answer: Option
Explanation:
Let the numbers be x and y.
Then, xy = 120 and x2 + y2 = 289.
(x + y)2 = x2 + y2 + 2xy = 289 + (2 x 120) = 529
x + y = 529 = 23.
Discussion:
13 comments Page 2 of 2.
Pavan said:
1 decade ago
@Abishek.
In this question we already know their products and sum of the squares of their products only one we have to find out is their sum. So here we are using (a+b)whole square formulae:
Hence we are adding 289+2(120).
In this question we already know their products and sum of the squares of their products only one we have to find out is their sum. So here we are using (a+b)whole square formulae:
Hence we are adding 289+2(120).
Abhishek Patel said:
1 decade ago
Can anybody make me understand, why in the given solution we are adding 240 in 289 whereas actually it should be deducted from 289.
(1)
Kumar said:
2 decades ago
The question makes no sense yaar. What does the question maker mean by saying 'sum of their sqaures'. A sense English means x^2+y^2 , but the solution shows (x+y)^2 [20+3] when the given question should have been like 20^2+3^2. The question should have been 'square of their sum' and not 'sum of their squares'.
(1)
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