Aptitude - Problems on Numbers - Discussion
Discussion Forum : Problems on Numbers - General Questions (Q.No. 10)
10.
Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.
Answer: Option
Explanation:
Let the number be x.
Then, x + 17 = | 60 |
x |
x2 + 17x - 60 = 0
(x + 20)(x - 3) = 0
x = 3.
Discussion:
21 comments Page 3 of 3.
Revathy said:
1 decade ago
(x+20)(x-3)=0 is correct
hw did you arrive on x = 3?
Please explain the solving of equation.
hw did you arrive on x = 3?
Please explain the solving of equation.
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