Aptitude - Problems on Numbers - Discussion

Discussion Forum : Problems on Numbers - General Questions (Q.No. 10)
10.
Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.
3
10
17
20
Answer: Option
Explanation:

Let the number be x.

Then, x + 17 = 60
x

x2 + 17x - 60 = 0

(x + 20)(x - 3) = 0

x = 3.

Discussion:
21 comments Page 3 of 3.

Revathy said:   1 decade ago
(x+20)(x-3)=0 is correct
hw did you arrive on x = 3?

Please explain the solving of equation.


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