Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 15)
15.
A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. After what time will they again at the starting point ?
Answer: Option
Explanation:
L.C.M. of 252, 308 and 198 = 2772.
So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.
Discussion:
66 comments Page 4 of 7.
Vandan said:
4 years ago
It's simple, we have to only take out lcm which is 2772 and then convert it into time.
(2)
Ramin said:
4 years ago
Simply divide 2772 by 60.
You will get 46.
And remainder 12.
The remainder is seconds.
You will get 46.
And remainder 12.
The remainder is seconds.
(3)
Zikpe said:
6 years ago
Just take LCM of 252, 308 & 198.
LCM = 2772 seconds or 46 minutes 12 seconds.
LCM = 2772 seconds or 46 minutes 12 seconds.
Syed Nadeem Asghar Rizvi said:
9 years ago
When I am doing 2772/60 (min) = 46.2 min is coming which means 46 mins. 2 secs.
Anyone said:
6 years ago
I have not understand what you said please show me the LCM how you have done.
(2)
Prahlad said:
8 years ago
2772 /60 =924/20 = 46minutes 4 seconds.
But 2772 /60 = 46minutes 12 seconds.
But 2772 /60 = 46minutes 12 seconds.
Jothi said:
8 years ago
Why we take LCM for this problem? How to understand. Anyone please tell me.
Priya said:
1 decade ago
I didn't understand how you took 2772 into 46 minutes and 12 seconds.
(1)
Ramya said:
1 decade ago
Can anyone tell me how to take quick L. C. M for big numbers? please.
Sandy said:
8 years ago
2400 sec= 40min and 360 sec = 6 min. Remaining 12 sec (2400+360+12).
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