Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 15)
15.
A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. After what time will they again at the starting point ?
Answer: Option
Explanation:
L.C.M. of 252, 308 and 198 = 2772.
So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.
Discussion:
66 comments Page 2 of 7.
Tapish said:
8 years ago
Three girls starting jogging from the same point around a circular track each one complete one round in 24 sec, 36 sec, 48 sec. Respectively after how much time will they meet at one point? Can anyone solve this?
Isa said:
1 decade ago
252 = 2x2x3x3x7
308 = 2x2x7x11
198 = 2x3x3x11
L.C.M. of the given numbers = product of all the prime factors of each of the given number with greatest index of common prime factors, so
2x2x3x3x7x11 = 2272
308 = 2x2x7x11
198 = 2x3x3x11
L.C.M. of the given numbers = product of all the prime factors of each of the given number with greatest index of common prime factors, so
2x2x3x3x7x11 = 2272
Dean said:
1 decade ago
It can't be determined unless the whole length of the track is given. Anyway, they will meet on the track again after 46 m 12 s but not necessarily at the starting point.
Sundar said:
1 decade ago
60 seconds = 1 minute
2760 seconds = 46 minute [Note: 2760/60 = 46]
Therefore,
2772 sec = 2760 + 12 seconds (or) 46 min 12 sec.
Hope you got it. Have a nice day!
2760 seconds = 46 minute [Note: 2760/60 = 46]
Therefore,
2772 sec = 2760 + 12 seconds (or) 46 min 12 sec.
Hope you got it. Have a nice day!
(3)
Shyam hyd said:
8 years ago
@JOTHI
2/ 252 308 198=126 154 99,
2/ 126 154 99= 63 77 99,
7/ 63 77 99,
11/ 9 11 9,
9/ 9 1 9 = 1 1 1,
2 * 2 * 7 * 9 * 11 = 2772.
2772 sec. i.e., 46 min. 12 sec.
2/ 252 308 198=126 154 99,
2/ 126 154 99= 63 77 99,
7/ 63 77 99,
11/ 9 11 9,
9/ 9 1 9 = 1 1 1,
2 * 2 * 7 * 9 * 11 = 2772.
2772 sec. i.e., 46 min. 12 sec.
Kinjal said:
9 years ago
@Teja.
For train and distance question this question has inadequate data as there is no speed or distance given, hence we have to take it as L.C.M question.
For train and distance question this question has inadequate data as there is no speed or distance given, hence we have to take it as L.C.M question.
Teja said:
10 years ago
After seeing this question I first thought, this question might be from TRAIN AND DISTANCE.
How can one know that we have to LCM for such kind of questions?
How can one know that we have to LCM for such kind of questions?
Karthi said:
1 decade ago
First note down in question, if they ask multiple number or factors.
Factors - denominators -solve hcf.
Multiple - numerators in fraction- solve lcm.
Factors - denominators -solve hcf.
Multiple - numerators in fraction- solve lcm.
Sanju said:
8 years ago
I didn't get the same answer (46.12 second). I got only 46.2 second.
How you got 46.12 seconds?
I divided 2772 /60 then I got 46.2 second.
How you got 46.12 seconds?
I divided 2772 /60 then I got 46.2 second.
Renuka said:
10 years ago
L.C.M means just remember that the highest number should be taken and common factor for the all given numbers. I hope yow will understand.
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