Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 3)
3.
Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ?
Answer: Option
Explanation:
L.C.M. of 2, 4, 6, 8, 10, 12 is 120.
So, the bells will toll together after every 120 seconds(2 minutes).
| In 30 minutes, they will toll together | 30 | + 1 = 16 times. |
| 2 |
Discussion:
170 comments Page 7 of 17.
Malan said:
8 years ago
How we get 120?
Harsha Shende said:
8 years ago
Please give me an answer of this problem.
Least number which when divided by 5, 6, 7, 8 and leaves remainder 3 but when divided by 9 leaves no remainder?
Least number which when divided by 5, 6, 7, 8 and leaves remainder 3 but when divided by 9 leaves no remainder?
Chandra mouli R said:
8 years ago
In the question, it clearly states that all the bell starts tolling at first and then tolls at regular intervals,
So we have to add 1 with the 15.
So we have to add 1 with the 15.
Harshini pusarla said:
8 years ago
Why 1 is added?
Chandan said:
8 years ago
Thanks for the great explanation @Sravanreddypailla.
Vishnu said:
8 years ago
Answer 15 is right.
The reason is we can't consider 0th sec bell together like in clock problem hour and min. Hand coincide 11 times in 12 hours.
The reason is we can't consider 0th sec bell together like in clock problem hour and min. Hand coincide 11 times in 12 hours.
Ramya said:
8 years ago
Excellent explanation @Sravanreddy.
NIDISH said:
8 years ago
If 6 bells takes 6 seconds then how much seconds does the 10 bells take? can anyone solve this?
Abhishek pandey said:
8 years ago
According to me, the answer is 15.
Sapana said:
8 years ago
How to calculate 120?
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