Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 3)
3.
Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ?
4
10
15
16
Answer: Option
Explanation:

L.C.M. of 2, 4, 6, 8, 10, 12 is 120.

So, the bells will toll together after every 120 seconds(2 minutes).

In 30 minutes, they will toll together 30 + 1 = 16 times.
2

Discussion:
170 comments Page 6 of 17.

Pri said:   1 decade ago
Please explain me HCM. I can't get clear idea about it.

Upendra said:   1 decade ago
Why 1 added?

Saikiran said:   1 decade ago
Six bells commence tolling together means six bells started tolling together that's why 1 is added to 15, now 15+1=16.

Commence=Start or begin.

Sumit chauhan said:   1 decade ago
But why are we add 1? Because when we toll together all the ball. They toll together. And that time also count in first 30 min.

Divi said:   1 decade ago
Very clear explanation. Thank you.

Shrinivasmutagar said:   1 decade ago
Why that 120 sec have been took?

Mahesh said:   10 years ago
How do you get that 120?

Gowthami said:   10 years ago
As they all together, why should we add 1, I couldn't understand. Why will first bell toll first, it starts together with the 5 bells know?

Akhil said:   10 years ago
4 bells ring at an interval of 12, 16, 20, 24 min if they start together at 9 am after how long will they ring together.

Sam said:   10 years ago
12 = 2*2*3.

16 = 2*2*2*2.

20 = 2*2*5.

24 = 3*2*2*2.

L.C.M = 2*2*2*2*3*5 = 240 min.

= 240 min/60 min = 4 hr.

So at 1 pm it will ring again (9+4).


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