Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 3)
3.
Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ?
4
10
15
16
Answer: Option
Explanation:

L.C.M. of 2, 4, 6, 8, 10, 12 is 120.

So, the bells will toll together after every 120 seconds(2 minutes).

In 30 minutes, they will toll together 30 + 1 = 16 times.
2

Discussion:
170 comments Page 3 of 17.

Ashu said:   5 years ago
How to find LCM for this? Please tell someone.

Avinash said:   5 years ago
@Shahrukh.

Here, it is mentioned that the bell starts after tolling thas why we add 1.

Sirichandana said:   5 years ago
Very well said, thanks @Sravan.

Shahrukh said:   6 years ago
Why is 1 being added? How can at 0 sec they toll together? So why adding 1? When 1st toll is after 2 min then at 30th min they will toll 15th time. Thats it.

Raksha said:   6 years ago
Why 1 is added please explain?

Surajbhan singh said:   6 years ago
Why 1 is added your answer in the question. Read it once again carefully.
(1)

Michael said:   6 years ago
Why 1 is added? Explain it.

Chojoy said:   6 years ago
You can also use AP(Arithmetic Progression) method to solve this problem.

Since the given tolling interval are in AP,ie 2 4 6 8 10 12........ , and nth time is 30min.

HENCE, using AP formula, we have;
T(N)=a+(n-1)d
a=2, d=4-2 ie d=2, n=?
30=2+(n-1)2
30=2+2n-2
ie, 30=2n
therefore, n=15.

Since we have to consider first toll, add+1 to n.
Therefore, the answer is 15+1=16.
(2)

Adithya said:   6 years ago
Thank you @Sundar.

ASHNA said:   6 years ago
Thanks @Saravan and @Deepak.


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