Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 14)
14.
The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:
Answer: Option
Explanation:
L.C.M. of 5, 6, 7, 8 = 840.
Required number is of the form 840k + 3
Least value of k for which (840k + 3) is divisible by 9 is k = 2.
Required number = (840 x 2 + 3) = 1683.
Discussion:
86 comments Page 8 of 9.
Anand said:
1 decade ago
The solution of finding the option which is divisible by 9 works only in this specific case of provided options. In case, when more than 1 option is divisible by 9, the method to find out the value of k needs to be understood.
Gogol said:
1 decade ago
@SUCHITA
If one of the option becomes for example..2538, then the sum of 2+5+3+8= 18 will also be divided by 9 leaving no remainder.
So, in this case there is no profit from your logic.
If one of the option becomes for example..2538, then the sum of 2+5+3+8= 18 will also be divided by 9 leaving no remainder.
So, in this case there is no profit from your logic.
M.V.KRISHNA/PALVONCHA said:
1 decade ago
Excellent suchita.
Simanta said:
1 decade ago
Nice suchita !
Shariq said:
1 decade ago
Just divide all options by 9.
Saurabh agrawal said:
1 decade ago
Suchita's trick is great. Very short and productive.
Gaurav said:
1 decade ago
You can find out whether any num is divisible by nine, 3, 4 by using divisibily test. Jus try google search for divisibility test.
Sakshi said:
1 decade ago
nice Mehar.
Uttam said:
1 decade ago
Just try this,
Sum the digits of each option given. i.e
[A].1+6+7+7=21 [B].1+6+8+3=18
[C].2+5+2+3=12 [D].3+3+6+3=15
Now only 18 is divisible by 9
So answer should be 1683 that is option B.
Sum the digits of each option given. i.e
[A].1+6+7+7=21 [B].1+6+8+3=18
[C].2+5+2+3=12 [D].3+3+6+3=15
Now only 18 is divisible by 9
So answer should be 1683 that is option B.
Mehar said:
1 decade ago
multiply all the values ==> 5*6*7*8=1680.
these are leaving 3 as a reminder so,1680+3=1683.
these are leaving 3 as a reminder so,1680+3=1683.
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