Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 14)
14.
The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:
1677
1683
2523
3363
Answer: Option
Explanation:

L.C.M. of 5, 6, 7, 8 = 840.

Required number is of the form 840k + 3

Least value of k for which (840k + 3) is divisible by 9 is k = 2.

Required number = (840 x 2 + 3) = 1683.

Discussion:
86 comments Page 3 of 9.

Shruti said:   8 years ago
@Suchita.

You are truly right this really works!

Must say this is the best Sol for this question. Thanks.

SURESH BINWAL said:   9 years ago
Any number whose digits sum is nine (9) then only the number is divisible by nine.

taking k = 1..means 843 , sum will be 8+4+3 = 15 not divisible by nine.

k = 2 is 1643 & sum of digit is 1+6+4+3 = 18 means 1+8 = 9 hence least number is k=2.

Samiul sk said:   9 years ago
Find the least number which when divided by 12, leaves a remainder of , when divided by 15, leaves a remainder of 10, when divided by 16, leaves a remainder of 11.

(a)115 (b)235 (c)247 (d)475

Solve and find the answer.

Tina Bhattacharjee said:   9 years ago
@Suchita.

18 is divisible by 6. There is no remainder. But as per the question, we should get 3 as the remainder when we divide the number by 6.

Sags. said:   9 years ago
Why are we using variable 'K'? Please tell the method not shortcut.

Akshay said:   9 years ago
Please tell me, how to find the value of k?

Vikram Rajput said:   9 years ago
Divide all options by number which is multiple in the question if remainder 0 for any option, that is your answer.

Anjali said:   7 years ago
Check the 4 options divisibility for 9.

Option B.
1+6+8+3=18 which is divisible by 9.
While other options are not divisible by 9.

Amendra said:   6 years ago
How does the value of k equals 2?

Bodla aravind said:   6 years ago
Let (840k + 3) = 1683 [ 1683 taken from Option B].
Therefore, k = (1683-3)/840.
k = 1680/840,
k= 2.


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