Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 14)
14.
The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:
Answer: Option
Explanation:
L.C.M. of 5, 6, 7, 8 = 840.
Required number is of the form 840k + 3
Least value of k for which (840k + 3) is divisible by 9 is k = 2.
Required number = (840 x 2 + 3) = 1683.
Discussion:
86 comments Page 3 of 9.
Lali said:
1 decade ago
It clear when we put a value of k 1 then 5,6,7,8, leave the remainder 3 and 6 in case of 9. when k=2. in this case no remainder is left.
Naveen said:
1 decade ago
840/9 =93 and leaves reminder 3.
Now 9*93 + (3 * x +3) now find the value of x in (3* x + 3) which is divisible by 9.
If you put 2 then it is divisible by 9 i.e., (3*2+3).
So k=2.
Now 9*93 + (3 * x +3) now find the value of x in (3* x + 3) which is divisible by 9.
If you put 2 then it is divisible by 9 i.e., (3*2+3).
So k=2.
Ramya said:
1 decade ago
Why we are using variable k?
Rd sharma said:
1 decade ago
In question when number is divided by 9 no reminder. If reminder is 2 then how can solve this question. Please reply anyone.
Kranthi said:
1 decade ago
If all the options divided by 9 then what we have to choose?
Priyanka Mishra said:
1 decade ago
@Kranthi you can check from the options by dividing the number by 5, 6, 7, 8 and find if the required remainder is coming or not.
Kannan said:
1 decade ago
In the below eqn.
Least value of k for which (840k + 3) is divisible by 9.
K can be K=0,1,2...
Sub K=1,
(840*1)+3 =-- Not divisible by 9.
Sub K=2,
(840*2)+3 = 187-- Divisible by 9.
Sub K=3,
(840*3)+3 =-- Not Divisible by 9.
Hence take lease no. (i.e 2).
Least value of k for which (840k + 3) is divisible by 9.
K can be K=0,1,2...
Sub K=1,
(840*1)+3 =-- Not divisible by 9.
Sub K=2,
(840*2)+3 = 187-- Divisible by 9.
Sub K=3,
(840*3)+3 =-- Not Divisible by 9.
Hence take lease no. (i.e 2).
(1)
Bujji said:
1 decade ago
Simply divide the options with 9 and which option whose remainder is 0 it is the answer.
Lavi said:
1 decade ago
Oh, its simple one. You have to check only options. As question said when divided by 9 leaves no remainder. Means you have to check the divisibility of 9.
Iswaryalakshmi said:
1 decade ago
If they don't give options how can I get 'k' value? Please explain.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers