Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 19)
19.
The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:
1008
1015
1022
1032
Answer: Option
Explanation:

Required number = (L.C.M. of 12,16, 18, 21, 28) + 7

   = 1008 + 7

   = 1015

Discussion:
28 comments Page 2 of 3.

Abhi said:   4 years ago
1015 which when diminished(subtracted) by 7 i.e.1008 this number will divisible by 12,16,18,21,28. so answer is 1015.

LCM of (12,16,18,21,28) = 1008.
(1)

RUPESH said:   8 years ago
Hey,

Just add the digits of given options as,

1+0+1+5=7 the answer is that which can be divided by 7.

Remaining numbers can't divide by 7.

Keerthi said:   1 decade ago
Let the smallest no be X,
Lcm of 12,16,18,21,28 = 1008.

Here in question, they have,
Diminished by 7, so, x-7 = 1008.

x = 1008+7 = 1015.

BINAY KUMAR said:   1 decade ago
7 is added because is LCM gives you that number which is seven less then required number mathematically prefer to previous comment.

Mahesh bhoi said:   1 decade ago
In question diminished by 7 means in option which no is diminish we will divided by 12, 16, 18, 21.

Maneesha said:   7 years ago
Least number = x
Then x-7 = lcm of 12, 16, 18, 21, 28.
x-7 = 1008,
x = 1008 + 7,
x = 1015.
(9)

Ashwin said:   6 years ago
simple trick guys,

1+0+1+5 = 7.
and 7/7 = 0 (reminder).

So, the answer is 1015.
(5)

AJAY said:   2 years ago
The answer is wrong correct answer is;.
Lcm (12, 16, 18, 21, 28) = 504 +7.
= 511.
(1)

Ansar mk said:   8 years ago
how we can find the LCM of this numbers easly?without using calclator.

Merry said:   1 decade ago
Please tell me details explain, I don't understand why you adding 7.


Post your comments here:

Your comments will be displayed after verification.