Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 5)
5.
The greatest number of four digits which is divisible by 15, 25, 40 and 75 is:
Answer: Option
Explanation:
Greatest number of 4-digits is 9999.
L.C.M. of 15, 25, 40 and 75 is 600.
On dividing 9999 by 600, the remainder is 399.
Required number (9999 - 399) = 9600.
Discussion:
120 comments Page 5 of 12.
Tejas Kumbhar said:
1 decade ago
The Logic here is this:
We have to find the greatest 4 digit number which is divisible by 15, 25, 40 and 75, hence it is a multiple of all these.
The LCM(15, 25, 40, 75) = 600 i.e. the least common multiple.
Hence all other common multiples of 15, 25, 40 and 75 will be multiples of 600 as well.
So to find the highest 4 digit one among all the common multiples, divide all the options by 600 to check which is perfectly divisible by 600. We get 9600, which is the answer.
We have to find the greatest 4 digit number which is divisible by 15, 25, 40 and 75, hence it is a multiple of all these.
The LCM(15, 25, 40, 75) = 600 i.e. the least common multiple.
Hence all other common multiples of 15, 25, 40 and 75 will be multiples of 600 as well.
So to find the highest 4 digit one among all the common multiples, divide all the options by 600 to check which is perfectly divisible by 600. We get 9600, which is the answer.
Shubhangi said:
1 decade ago
Why do we take LCM of the given numbers, but not HCF?
Sanesh said:
1 decade ago
How you get 399?
Heena said:
1 decade ago
We can also take 9800 as a base then we have to divide 9800 by 600 which gives 200 remainder and we subtract 200 from 9800 will give the answer 9600.
Atul said:
1 decade ago
How to devide 9999 by 600? please explain.
Rohir said:
1 decade ago
How that remainder come 399 please tell me?
Veeramani said:
1 decade ago
9999 divide 600 which give only remainder for 133 but there they are said 399 how its?
Anil said:
1 decade ago
What if we take 6 digits?
Siddharth said:
1 decade ago
Hi all,
Another method to answer this question is just break all four (15, 25, 40, 75) in to prime numbers.
15 = 5*3.
25 = 5*5.
40 = 8 (2*2*2) *5.
75 = 5*3*5.
Now here we can see the common divisors are 5, 3 and 8.
So the number which is divisible by 5, 3 and 8 is the right answer which is option C 9600.
Another method to answer this question is just break all four (15, 25, 40, 75) in to prime numbers.
15 = 5*3.
25 = 5*5.
40 = 8 (2*2*2) *5.
75 = 5*3*5.
Now here we can see the common divisors are 5, 3 and 8.
So the number which is divisible by 5, 3 and 8 is the right answer which is option C 9600.
Sagar said:
1 decade ago
How remainder 399 comes, by my calculation remainder must be 133? Please show the remainder calculation.
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