Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Answer: Option
Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
Discussion:
210 comments Page 15 of 21.
Jaggu said:
1 decade ago
43%4 = 3.
91%4 = 3.
183%4 = 3.
That's why answer is 4.
91%4 = 3.
183%4 = 3.
That's why answer is 4.
Vidhya said:
1 decade ago
Why we have to take the difference of those two numbers?
Manindra said:
1 decade ago
We take difference as it is very simple for calculation.
Vamshi said:
1 decade ago
48, 92 and 140 = 4 how now am confusing, please explain.
Lokesh said:
8 years ago
Easy to understand. Thanks to all the given explanation.
Tejveer said:
5 years ago
@Karthik V.
Great explanation, Thanks for solving this.
Great explanation, Thanks for solving this.
Sakthi said:
5 years ago
Why they took difference here? Anyone explain about it.
Ayesha said:
3 years ago
I am not understanding this. Please explain in detail.
(17)
Raj said:
2 decades ago
Why do we do the difference of number to each other?
(1)
Yuva kumar said:
1 decade ago
Dear Sir/madam please expain I could not understand.
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