Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Answer: Option
Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
Discussion:
212 comments Page 12 of 22.
VIGNESH KUMAR said:
1 decade ago
Simple way to calculate HCF:
2|48 92 140
-----------
2|24 46 70
-----------
|12 23 35
------------
Stop if you can't divide by common divisor, so answer = 2*2 = 4.
2|48 92 140
-----------
2|24 46 70
-----------
|12 23 35
------------
Stop if you can't divide by common divisor, so answer = 2*2 = 4.
Mandeep said:
1 decade ago
@Prashant.
P is not a dividend its divisor.
P is not a dividend its divisor.
Vamshi said:
1 decade ago
48, 92 and 140 = 4 how now am confusing, please explain.
Dhananjay said:
1 decade ago
@ Sanddep:
Have a look at explanation given by @Prasant. We have to solve equation for 'p'. Hence,we eliminate 'r' by taking differences of numbers.
Have a look at explanation given by @Prasant. We have to solve equation for 'p'. Hence,we eliminate 'r' by taking differences of numbers.
Dove said:
1 decade ago
I don't understand why you write 2*2 and say the answer is 4.
Neeraj said:
1 decade ago
Why we take HCF? When one should take LCM and HCF.
Sandeep said:
1 decade ago
Why did we take the differences of the numbers?
Is this the only way to solve it by taking the differences if there is any other method then please reply?
Is this the only way to solve it by taking the differences if there is any other method then please reply?
Honey said:
1 decade ago
Here 4 is even number. So its multiples will also be even. In the question above all the numbers were odd. If is divide by 4 then it will compulsory leaves an remainder.
Lakhan saini said:
1 decade ago
Divided by 4 each number we get remainder 3
Govind Paswan said:
1 decade ago
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Explanation: 43, 91, 183.
183 = (183-91) = 92.
91 = (183-43) = 140.
43 = (91-43) = 48.
92, 140, 48.
92 = 2*2*23.
140 = 2*2*35.
48 = 2*2*2*3*2.
Ans 4.
Explanation: 43, 91, 183.
183 = (183-91) = 92.
91 = (183-43) = 140.
43 = (91-43) = 48.
92, 140, 48.
92 = 2*2*23.
140 = 2*2*35.
48 = 2*2*2*3*2.
Ans 4.
(1)
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